ATI TEAS 7
TEAS 7 practice test science
1. What is the technical term for the involuntary muscular contractions that move food through the digestive tract?
- A. Segmentation
- B. Peristalsis
- C. Chylification
- D. Emulsification
Correct answer: B
Rationale: Peristalsis is the term used to describe the involuntary muscular contractions that move food through the digestive tract. This process involves rhythmic contractions and relaxations of the muscles in the digestive system, which help propel food from the esophagus to the stomach and through the intestines for digestion and absorption of nutrients. Segmentation refers to the mixing movements in the intestines that aid in the absorption of nutrients but is not the term for the movement of food through the digestive tract. Chylification is not a recognized term in digestive physiology. Emulsification is the process of breaking down fat globules into smaller droplets to aid in digestion, not the movement of food through the digestive tract.
2. Antibiotic resistance in bacteria is an example of:
- A. Convergent evolution
- B. Divergent evolution
- C. Microevolution
- D. Macroevolution
Correct answer: C
Rationale: Antibiotic resistance in bacteria is a classic example of microevolution (option C). Microevolution refers to changes in allele frequencies within a population over a relatively short period of time. In the case of antibiotic resistance, bacteria evolve resistance to antibiotics through the natural selection of pre-existing resistant strains. This process does not involve the formation of new species or higher taxonomic groups, which are associated with macroevolution (option D). Convergent evolution (option A) involves different species independently evolving similar traits in response to similar environmental pressures, which is not the case with antibiotic resistance in bacteria. Divergent evolution (option B) refers to related species becoming more dissimilar over time, which also does not apply to the scenario of antibiotic resistance in bacteria.
3. Which of the following colligative properties refers to the elevation of the boiling point of a solution?
- A. Freezing point depression
- B. Vapor pressure lowering
- C. Osmotic pressure
- D. Boiling point elevation
Correct answer: D
Rationale: The correct answer is D, 'Boiling point elevation.' Boiling point elevation is a colligative property that describes the increase in the boiling point of a solvent when a non-volatile solute is added to it. This occurs because the presence of solute particles in the solvent lowers the vapor pressure of the solution, requiring a higher temperature to reach the same vapor pressure as the pure solvent. Choices A, B, and C are incorrect. Freezing point depression refers to the lowering of the freezing point of a solution, vapor pressure lowering is the reduction in vapor pressure due to the presence of solute particles, and osmotic pressure is the pressure required to prevent the flow of solvent molecules across a semipermeable membrane in osmosis.
4. What is a monohybrid cross, and what is the ratio of dominant to recessive gene manifestation?
- A. A cross involving two traits, 9:3:3:1
- B. A cross involving one trait, 3:1
- C. A cross involving two traits, 1:2:1
- D. A cross involving one trait, 1:1
Correct answer: B
Rationale: A monohybrid cross is a genetic cross involving one trait. The ratio of dominant to recessive gene manifestation in the offspring is typically 3:1 when both parents are heterozygous. This ratio is the genotypic ratio, not just the phenotype ratio, where the dominant allele is present in 3 out of 4 offspring, and the recessive allele is present in 1 out of 4 offspring. Choice A is incorrect because it describes a dihybrid cross ratio. Choice C is incorrect as it represents the genotypic ratio for a monohybrid cross involving incomplete dominance. Choice D is incorrect as it does not reflect the typical ratio for a monohybrid cross.
5. What is the temperature of 35°C in Kelvin?
- A. 220
- B. 238
- C. 308
- D. 345
Correct answer: C
Rationale: To convert Celsius to Kelvin, add 273.15 to the Celsius temperature. In this case, 35°C + 273.15 = 308.15 K. Therefore, the correct answer is 308 K. Choice A (220) is incorrect as it does not account for adding 273.15 to convert to Kelvin. Choice B (238) is incorrect as it is not the result of adding 273.15 to 35°C. Choice D (345) is incorrect as it is not the correct conversion of 35°C to Kelvin.
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