ATI TEAS 7
TEAS 7 science study guide free
1. What is the process of cells becoming specialized to perform specific functions called?
- A. Cell division
- B. Cell differentiation
- C. Cell growth
- D. Cell regeneration
Correct answer: B
Rationale: Cell differentiation is the process by which cells become specialized to perform specific functions. During differentiation, cells acquire specific structures and functions that allow them to carry out particular roles in the body. Cell division refers to the process by which a parent cell divides into two or more daughter cells. Cell growth is the process by which cells increase in size and number. Cell regeneration is the process by which new cells are produced to replace damaged or lost cells in an organism. Therefore, in this context, the process of cells becoming specialized to perform specific functions is best described as cell differentiation.
2. What is a benefit of a taxonomic system?
- A. Researchers can describe how living things behave.
- B. Researchers can develop names for new organisms.
- C. Living things can be distinguished from nonliving things.
- D. Living things can be classified based on their molecular traits.
Correct answer: D
Rationale: The correct answer is D. A taxonomic system allows scientists to classify living organisms based on their molecular and genetic traits. This classification helps in understanding the relationships and evolutionary history of different organisms, providing insights into their characteristics and behaviors. Choices A, B, and C do not directly relate to the primary purpose and benefit of a taxonomic system, which is the systematic classification of organisms.
3. The Becquerel (Bq) is the designated unit for quantifying:
- A. Electron volt (eV) measurements of energy
- B. Radioactivity
- C. Electric charge (Coulombs)
- D. Force (Newtons)
Correct answer: B
Rationale: The Becquerel (Bq) is the unit used to measure radioactivity, specifically the activity of a quantity of radioactive material. It represents the number of radioactive disintegrations or transformations per unit of time. Choice A, electron volt (eV), is a unit of energy, not radioactivity. Choice C, electric charge (Coulombs), is measured in Coulombs, not Becquerels. Choice D, force (Newtons), is a unit of force, not radioactivity. Therefore, the correct answer is B.
4. Which molecules are soluble in nonpolar solvents but are hydrophobic?
- A. Carbohydrates
- B. Lipids
- C. Proteins
- D. Nucleic acids
Correct answer: B
Rationale: Lipids are hydrophobic molecules that are soluble in nonpolar solvents like oils but insoluble in water. They consist of fats, oils, waxes, and steroids and play essential roles in energy storage, insulation, and cell membrane structure. Carbohydrates, proteins, and nucleic acids are not typically soluble in nonpolar solvents and do not exhibit the same hydrophobic characteristics as lipids. Carbohydrates are usually hydrophilic and soluble in water, proteins have both hydrophilic and hydrophobic regions but are not generally soluble in nonpolar solvents, and nucleic acids are polar molecules that are not known for their solubility in nonpolar solvents.
5. Which structure allows for the selective passage of materials into and out of the cell?
- A. DNA
- B. Protein
- C. Carbohydrate
- D. Phospholipid bilayer
Correct answer: D
Rationale: The phospholipid bilayer is a crucial component of the cell membrane, surrounding the cell and regulating the passage of materials into and out of the cell. Its structure enables it to be selectively permeable, controlling which substances can pass through. DNA, proteins, and carbohydrates are essential molecules in the cell but do not directly govern the passage of materials like the phospholipid bilayer does. Therefore, the correct answer is the phospholipid bilayer.
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