Nursing Elites

1. What is the primary function of red blood cells?

• A. To transport nutrients
• B. To transport oxygen
• C. To fight infection
• D. To produce antibodies

Correct answer: B

Rationale: The correct answer is B: To transport oxygen. Red blood cells play a crucial role in carrying oxygen from the lungs to all the tissues and organs in the body. This oxygen transport is essential for cellular respiration, where oxygen is used in the production of energy. Red blood cells do not primarily transport nutrients, fight infection, or produce antibodies. Choice A is incorrect because while red blood cells do carry some nutrients, their primary function is to transport oxygen. Choice C is incorrect because immune cells, not red blood cells, are responsible for fighting infections. Choice D is incorrect as antibody production is mainly carried out by specialized white blood cells, not red blood cells.

2. Which factor do colligative properties of solutions depend on?

• A. Concentration of the solvent
• B. All of the above
• C. Chemical identity of the solute
• D. Number of solute particles in solution

Correct answer: D

Rationale: Colligative properties of solutions depend on the number of solute particles in solution. These properties, such as boiling point elevation, freezing point depression, vapor pressure lowering, and osmotic pressure, are proportional to the number of solute particles present in the solution. The chemical identity of the solute or the concentration of the solvent does not influence colligative properties, making choices A and C incorrect. Therefore, the correct answer is D, the number of solute particles in solution.

3. What is the correct arrangement of the small intestine segments, from the stomach to the large intestine?

• A. Duodenum, Jejunum, Ileum
• B. Jejunum, Ileum, Duodenum
• C. Ileum, Duodenum, Jejunum
• D. None of the above

Correct answer: A

Rationale: The correct arrangement of the small intestine segments, from the stomach to the large intestine, is Duodenum, Jejunum, and Ileum. The small intestine begins with the duodenum, then continues to the jejunum, and finally, it ends with the ileum before connecting to the large intestine. Option A, 'Duodenum, Jejunum, Ileum,' is the correct sequence. Choices B and C have the segments in incorrect order, not following the anatomical arrangement of the small intestine. Therefore, they are incorrect. Option D, 'None of the above,' is also incorrect as the correct sequence is provided in option A.

4. In physics, what does the term 'terminal velocity' refer to?

• A. Maximum velocity reached by an object in free fall
• B. Velocity when the object is at rest
• C. Instantaneous velocity of an object
• D. Velocity only reached by heavy objects

Correct answer: A

Rationale: Terminal velocity in physics refers to the maximum velocity achieved by an object in free fall when the force of gravity equals the force of air resistance. At terminal velocity, the object stops accelerating and maintains a constant speed. This occurs when the opposing forces are balanced, leading to no further increase in speed. Choice B is incorrect as velocity when the object is at rest is zero, not at terminal velocity. Choice C is incorrect as instantaneous velocity refers to the velocity at a specific moment in time, not the maximum speed reached in free fall. Choice D is incorrect because terminal velocity is not exclusive to heavy objects; all objects in free fall can reach terminal velocity under the right conditions.

5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

• A. 18.3 g
• B. 19.7 g
• C. 21.0 g
• D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

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