Nursing Elites

1. What is the outermost layer of the dermis, rich in collagen and elastin fibers that provide elasticity to the skin?

• A. Papillary layer
• B. Reticular layer
• C. Stratum basale
• D. Stratum corneum

Correct answer: B

Rationale: The correct answer is the reticular layer. This layer is the outermost layer of the dermis that contains abundant collagen and elastin fibers, providing elasticity to the skin. The papillary layer is located beneath the epidermis and is responsible for supplying nutrients to the epidermis, not the outermost layer. The stratum basale is the deepest layer of the epidermis where new skin cells are produced, not part of the dermis. The stratum corneum is the outermost layer of the epidermis composed of dead skin cells, not a layer of the dermis.

2. Which of the following terms refers to a muscle that lengthens while another muscle contracts to produce movement?

• A. Synergist
• B. Agonist
• C. Antagonist
• D. Flexor

Correct answer: C

Rationale: The correct answer is 'Antagonist.' An antagonist muscle is a muscle that lengthens while another muscle (agonist) contracts to produce movement. The antagonist muscle relaxes to allow the agonist muscle to contract effectively. In this scenario, the antagonist muscle works in opposition to the agonist muscle, providing control and precision to movement. The other choices are incorrect because a synergist muscle assists the agonist muscle in performing a movement, an agonist muscle is the primary muscle responsible for generating movement, and a flexor muscle is a muscle that decreases the angle at a joint.

3. How can the peripheral nervous system be further divided?

• A. Sensory and motor
• B. Sympathetic and parasympathetic
• C. Myelinated and unmyelinated
• D. Central and peripheral

Correct answer: A

Rationale: The peripheral nervous system can be further divided into sensory (afferent) neurons that carry information from sensory receptors to the central nervous system and motor (efferent) neurons that carry information from the central nervous system to muscles and glands. Choice A, 'Sensory and motor,' is the correct answer as it accurately identifies the two main functional divisions of the peripheral nervous system. Choices B, 'Sympathetic and parasympathetic,' are divisions of the autonomic nervous system, not the peripheral nervous system. Choice C, 'Myelinated and unmyelinated,' refers to the structural classification of nerve fibers rather than functional divisions. Choice D, 'Central and peripheral,' contrasts the central nervous system with the peripheral nervous system, not further dividing the peripheral nervous system itself.

4. Which level of protein structure is defined by the folds and coils of the protein's polypeptide backbone?

• A. Primary
• B. Secondary
• C. Tertiary
• D. Quaternary

Correct answer: B

Rationale: The correct answer is B: Secondary. The secondary structure of a protein is defined by the folds and coils of the protein's polypeptide backbone. This level of structure is characterized by the formation of alpha helices and beta sheets, which are stabilized by hydrogen bonds between amino acids along the polypeptide chain. Choice A, Primary, refers to the linear sequence of amino acids in the protein. Choice C, Tertiary, involves the 3D folding of the entire polypeptide chain. Choice D, Quaternary, pertains to the arrangement of multiple polypeptide subunits in a protein complex.

5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

• A. 18.3 g
• B. 19.7 g
• C. 21.0 g
• D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

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