ATI TEAS 7
TEAS 7 science practice
1. What is the coefficient of oxygen in the balanced chemical equation for the combustion of methane (CHâ‚„)?
- A. 1
- B. 2
- C. 3
- D. 4
Correct answer: B
Rationale: In the balanced chemical equation for the combustion of methane, CH₄ + 2O₂ → CO₂ + 2H₂O, the coefficient of oxygen (O₂) is 2. This indicates that two molecules of oxygen are required to react with one molecule of methane to produce carbon dioxide and water, ensuring the equation is balanced. Choice A is incorrect because the coefficient of oxygen is not 1 but 2. Choices C and D are incorrect as they do not represent the correct coefficient of oxygen in the balanced equation. Understanding the coefficients in a balanced chemical equation is crucial for accurately representing the stoichiometry of the reaction.
2. How does an increase in surface area affect the force of friction between two surfaces?
- A. Increases friction
- B. Decreases friction
- C. Has no effect on friction
- D. Causes unpredictable changes in friction
Correct answer: A
Rationale: An increase in surface area typically increases the force of friction between two surfaces. This is because with a larger surface area in contact, there are more points of contact between the surfaces, leading to a greater frictional force resisting motion. As a result, the correct answer is that an increase in surface area increases the force of friction between two surfaces. Choice B is incorrect because a greater surface area increases the frictional force. Choice C is incorrect because an increase in surface area results in more contact points and greater friction. Choice D is incorrect as the relationship between surface area and friction is predictable - an increase in surface area generally leads to an increase in frictional force.
3. What happens to the internal energy of a system when it performs work on its surroundings?
- A. It increases.
- B. It decreases.
- C. It remains the same.
- D. Insufficient information.
Correct answer: B
Rationale: When a system performs work on its surroundings, it loses energy in the form of work done. This results in a decrease in the internal energy of the system. Work done by the system is considered as negative work, leading to a decrease in internal energy. Therefore, the correct answer is that the internal energy decreases when a system performs work on its surroundings. Choice A is incorrect as the internal energy decreases, not increases. Choice C is incorrect because the internal energy changes due to the work done. Choice D is incorrect because the information provided is sufficient to determine the change in internal energy.
4. What is a temporary loss of consciousness due to insufficient blood flow to the brain called?
- A. Stroke
- B. Seizure
- C. Syncope (fainting)
- D. Coma
Correct answer: C
Rationale: Syncope, also known as fainting, is a temporary loss of consciousness caused by insufficient blood flow to the brain. It results from a brief interruption in the brain's blood supply, leading to a temporary loss of consciousness. The correct answer is C. A stroke, option A, is caused by a blockage or rupture of blood vessels in the brain, not insufficient blood flow. Seizure, option B, involves a sudden surge of electrical brain activity, not reduced blood flow. Coma, option D, is characterized by prolonged unconsciousness, not a temporary loss of consciousness due to insufficient blood flow.
5. What is the process of removing waste products from the cell called?
- A. Exocytosis
- B. Endocytosis
- C. Phagocytosis
- D. Pinocytosis
Correct answer: A
Rationale: A) Exocytosis is the process by which cells expel waste products or other substances by fusing a vesicle containing the waste with the cell membrane, releasing its contents outside the cell. This process is essential for maintaining cellular homeostasis by removing waste products from the cell. B) Endocytosis is the process by which cells take in substances by engulfing them in a vesicle formed from the cell membrane. This process is the opposite of exocytosis and is used to bring substances into the cell. C) Phagocytosis is a type of endocytosis where cells engulf solid particles or other cells to form a vesicle called a phagosome. This process is used by immune cells to engulf and destroy pathogens. D) Pinocytosis is a type of endocytosis where cells engulf fluids and dissolved solutes. This process allows cells to take in nutrients.
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