Nursing Elites

1. What is the acceleration of an object moving at a constant speed of 20 m/s if it comes to a complete stop within 5 seconds?

• A. 0 m/s² (no acceleration)
• B. 4 m/s²
• C. -4 m/s²
• D. Insufficient information

Correct answer: C

Rationale: To find the acceleration, we use the formula: acceleration = (final velocity - initial velocity) / time. Given that the final velocity is 0 m/s (as the object stops), the initial velocity is 20 m/s, and the time taken is 5 seconds. Substituting these values into the formula, we get acceleration = (0 m/s - 20 m/s) / 5 s = -20 m/s / 5 s = -4 m/s². Therefore, the acceleration is -4 m/s², indicating that the object decelerated at a rate of 4 m/s² to come to a complete stop. Choice A is incorrect because the object does experience acceleration as it changes its speed from 20 m/s to 0 m/s. Choice B is incorrect as it represents acceleration in the wrong direction, considering the object is decelerating. Choice D is incorrect as there is sufficient information provided to calculate the acceleration based on the given data.

2. A person pushes a box across a floor with a constant force. The box eventually comes to a stop due to friction. What happens to the work done by the person?

• A. It increases as the box moves further.
• B. It decreases as the box slows down.
• C. It remains constant throughout the motion.
• D. It becomes zero once the box stops.

Correct answer: D

Rationale: Work done is defined as the product of the force applied and the distance moved in the direction of the force. In this scenario, when the box comes to a stop, the displacement becomes zero, leading to zero work done by the person. Choice A is incorrect as the work done is not increasing, but rather decreasing as the box slows down. Choice B is incorrect because the work done does not decrease as the box slows down; it becomes zero when the box stops. Choice C is incorrect as the work done is not constant but decreases to zero when the box stops.

3. How does the amplitude of a wave relate to its intensity or loudness?

• A. They are inversely proportional.
• B. They are directly proportional.
• C. They have no relationship.
• D. Amplitude affects frequency, not intensity.

Correct answer: B

Rationale: The amplitude of a wave is directly related to its intensity or loudness. In general, the larger the amplitude of a wave, the greater its intensity or loudness. This relationship is due to the fact that the amplitude of a wave represents the maximum displacement of particles in the medium from their rest position. The greater the displacement, the more energy the wave carries, leading to higher intensity or louder sound. Choice A is incorrect because the relationship between amplitude and intensity is direct, not inverse. Choice C is incorrect as there is a clear relationship between amplitude and intensity. Choice D is incorrect as amplitude primarily affects intensity or loudness, not frequency.

4. What term describes the point where parallel rays of light converge or appear to diverge after passing through a lens or reflecting off a mirror?

• A. Aperture
• B. Focal length
• C. Refractive index
• D. Lens thickness

Correct answer: B

Rationale: The correct answer is 'Focal length.' Focal length is the term used to describe the point where parallel rays of light converge or appear to diverge after passing through a lens or reflecting off a mirror. It is a critical parameter in optics that determines the magnification and image formation in optical systems. Aperture refers to the opening through which light enters a camera or telescope, not the convergence point of light rays. Refractive index is a measure of how much light is bent, not the point where rays converge. Lens thickness is the physical dimension of a lens and does not indicate the convergence point of light rays. Therefore, 'Focal length' is the most appropriate choice in this context.

5. How does the potential energy of an object change when it is compressed?

• A. Potential energy decreases
• B. Potential energy increases
• C. Potential energy remains constant
• D. Potential energy becomes zero

Correct answer: B

Rationale: When an object is compressed, its potential energy increases. This is because work is done on the object to compress it, resulting in an increase in potential energy stored in the object as it is compressed against an opposing force. The potential energy is transformed and stored within the object due to the work done during the compression process, leading to an increase in its potential energy. Choice A is incorrect because compression involves doing work on the object, increasing its potential energy. Choice C is incorrect because compression involves a change in position and potential energy. Choice D is incorrect because compression does not reduce potential energy to zero; rather, it increases it due to the work done in compressing the object.

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