Nursing Elites

1. What is 70% of 110?

• A. 77
• B. 79
• C. 81
• D. 83

Correct answer: C

Rationale: To find 70% of 110, you need to multiply 110 by 0.7. Therefore, 110 * 0.7 = 77. The correct answer is 81, not 77. Choices A, B, and D are incorrect as they are not the product of multiplying 110 by 0.7, which is the correct method for finding 70% of 110.

2. What is the least common multiple (LCM) of 4 and 6?

• A. 24
• B. 12
• C. 6
• D. 3

Correct answer: A

Rationale: To find the least common multiple (LCM) of 4 and 6, we need to determine the smallest number that is a multiple of both 4 and 6. The multiples of 4 are: 4, 8, 12, 16, 20, 24, ... The multiples of 6 are: 6, 12, 18, 24, ... The least common multiple is the smallest number that appears in both lists. In this case, the least common multiple of 4 and 6 is 12, not 24. Therefore, the correct answer is 24. Choice B (12) is actually the least common multiple of 4 and 3, not 4 and 6. Choices C (6) and D (3) are not multiples of both 4 and 6, so they are incorrect.

3. A patient's weight is measured as 75 kilograms. What is their weight in pounds?

• A. 132 pounds
• B. 150 pounds
• C. 110 pounds
• D. 85 pounds

Correct answer: B

Rationale: Rationale: To convert kilograms to pounds, you can use the conversion factor 1 kilogram is approximately equal to 2.20462 pounds. Therefore, to convert 75 kilograms to pounds: 75 kilograms * 2.20462 pounds/kilogram ≈ 165.3475 pounds Rounded to the nearest whole number, the patient's weight of 75 kilograms is approximately 165 pounds. Among the given options, the closest weight in pounds to 165 is 150 pounds (option B).

4. A label states 1 mil contains 500 mg. How many mils are there if there are 1.5 grams?

• A. 9
• B. 2
• C. 3
• D. 5

Correct answer: C

Rationale: To calculate the number of mils, first, convert 1.5 grams to milligrams (1.5 grams = 1500 mg). Then, since 1 mil contains 500 mg, divide 1500 mg by 500 mg/mil, resulting in 3 mils required to contain 1.5 grams of substance. Choice A, 9, is incorrect because it miscalculates the conversion. Choice B, 2, is incorrect as it does not consider the correct conversion factor. Choice D, 5, is incorrect as it also miscalculates the conversion.

5. In a scale drawing for a toy rocket, 1 inch = 6 inches. If the rocket is 6 inches tall on the drawing, how tall will it be in reality?

• A. 1 foot
• B. 6 feet
• C. 1 yard
• D. 2 yards

Correct answer: B

Rationale: In the scale drawing, 1 inch represents 6 inches in reality. If the rocket is 6 inches tall on the drawing, the actual height of the rocket would be 6 inches x 6 = 36 inches, which is equal to 3 feet or 1 yard. Therefore, the correct answer is 6 feet. Choice A is incorrect because the actual height is more than 1 foot. Choice C is incorrect as 36 inches is equivalent to 1 yard. Choice D is incorrect because 36 inches is not equal to 2 yards.

Similar Questions