the resolution of an optical instrument like a microscope refers to its ability to distinguish between
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ATI TEAS 7

TEAS 7 science practice questions

1. The resolution of an optical instrument, like a microscope, refers to its ability to distinguish between:

Correct answer: D

Rationale: The resolution of an optical instrument, such as a microscope, refers to its ability to distinguish between very close, nearly identical objects. This is crucial in microscopy to clearly visualize and differentiate fine details and structures. Resolving power plays a significant role in determining the quality and effectiveness of an optical instrument. Choices A, B, and C are incorrect because the resolution of an optical instrument does not primarily deal with different colors of light, presence or absence of light, or variations in intensity. Instead, it specifically focuses on the instrument's ability to differentiate between objects that are very close and nearly identical in nature.

2. What type of joint connects the bones of the skull?

Correct answer: B

Rationale: The correct answer is B: Fibrous joint. Fibrous joints connect the bones of the skull, providing stability with little to no movement. These joints are made of fibrous connective tissue, which holds the bones tightly together and prevents movement, making them ideal for the structure of the skull. Choice A: Hinge joint is incorrect because hinge joints allow movement in a single plane like the elbow or knee, which is not characteristic of the joints in the skull. Choice C: Ball-and-socket joint is incorrect as this type of joint allows for a wide range of movement in multiple planes, such as the hip and shoulder joints, which is not the case for skull bones. Choice D: Pivot joint is incorrect as pivot joints allow rotation around a central axis, as seen in the joint between the first and second cervical vertebrae (atlas and axis), but not in the skull bones.

3. A guitar string vibrates at a fundamental frequency of 440 Hz. What is the frequency of the second harmonic (first overtone)?

Correct answer: C

Rationale: The second harmonic (first overtone) is twice the frequency of the fundamental frequency. Therefore, the frequency of the second harmonic is 440 Hz * 2 = 880 Hz. The second harmonic has a frequency that is one octave higher than the fundamental frequency, representing the first overtone of the vibrating string. Choice A (220 Hz) is incorrect as it represents half the fundamental frequency and is the second harmonic, not the first overtone. Choice B (440 Hz) is the fundamental frequency itself. Choice D (1760 Hz) is the frequency of the fourth harmonic, not the second harmonic.

4. What are fingernails and toenails primarily made of?

Correct answer: B

Rationale: Fingernails and toenails are primarily made of a protein called keratin. Keratin is a tough, fibrous protein that provides structure and strength to nails, hair, and the outer layer of skin. Collagen, as mentioned, is found in the dermis and is not the primary component of nails. Melanin provides pigment to the skin and hair, not the structure of nails. Sebum is an oily substance produced by the skin's sebaceous glands and is not a structural component of nails.

5. What presents the correct order of cellular respiration?

Correct answer: A

Rationale: The correct order of cellular respiration is Glycolysis, Acetyl-CoA, Citric Acid Cycle, and Electron Transport Chain. Glycolysis initiates the breakdown of glucose in the cytoplasm, leading to the formation of pyruvate. This pyruvate is then converted to Acetyl-CoA in the mitochondria, which enters the Citric Acid Cycle to generate energy-rich molecules like NADH and FADH2. Finally, the Electron Transport Chain, located in the inner mitochondrial membrane, utilizes these energy carriers to produce ATP through oxidative phosphorylation. Choice B is incorrect because it starts with the Citric Acid Cycle, which comes after Glycolysis. Choice C is incorrect as it places the Citric Acid Cycle before the Electron Transport Chain. Choice D is incorrect by placing Acetyl-CoA last instead of before the Citric Acid Cycle.

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