HESI A2
HESI A2 Math Practice Exam
1. Sally was able to eat 5/8 of her lunch. John ate 75% of his lunch. Who ate more?
- A. John
- B. Sally
- C. Both ate the same
- D. Cannot be determined
Correct answer: A
Rationale: To compare the portions eaten by Sally and John, it's necessary to express both in the same denominator. Since 75% is equivalent to 6/8, John ate 6/8 while Sally ate 5/8 of their lunches. Therefore, John ate more than Sally. Choice A is correct. Choice B is incorrect as John ate 6/8 compared to Sally's 5/8. Choice C is incorrect as the amounts eaten are different. Choice D is incorrect as it can be determined based on the given information.
2. Repeating decimals can be expressed as fractions. Which of the following represents the decimal 0.7777... as a fraction?
- A. 77/1000
- B. 70/99
- C. 777/900
- D. 7/9
Correct answer: D
Rationale: To express the repeating decimal 0.7777... as a fraction, let x = 0.7777... Multiplying both sides by 10 to shift the decimal point to the right gives: 10x = 7.7777... Subtracting the original equation from the new equation eliminates the repeating decimal: 10x - x = 7.7777... - 0.7777... 9x = 7 x = 7/9. Therefore, the decimal 0.7777... can be expressed as the fraction 7/9. Choices A, B, and C are incorrect as they do not accurately represent the decimal 0.7777... when converted to a fraction.
3. Solve for y if y = 3: 4y + 21/y
- A. 19
- B. 7.7
- C. 23/3
- D. 11
Correct answer: A
Rationale: To solve the expression 4y + 21/y when y = 3, substitute y = 3: 4 * 3 + 21 / 3 = 12 + 7 = 19. Therefore, the correct answer is 19. Choice A, '19,' is the correct result of the expression when y = 3. Choice B, '7.7,' is incorrect as the correct answer is an integer, not a decimal. Choice C, '23/3,' is incorrect as it is not the simplified integer result of the expression. Choice D, '11,' is incorrect as it does not result from the given expression when y = 3.
4. Sergeant Kellogg had his men line up at 3:40 P.M. What would that be in military time?
- A. 340
- B. 3040
- C. 1500
- D. 1540
Correct answer: D
Rationale: In military time, the 24-hour clock is used. 3:40 P.M. in standard time would be 1540 in military time. To convert from standard time to military time, you keep the hour number the same for afternoon and evening hours but add 12 to afternoon hours. Choice A (340) is incorrect as it doesn't follow the military time format. Choice B (3040) is incorrect as military time uses a maximum of four digits. Choice C (1500) is incorrect as it represents 3:00 P.M. in military time, not 3:40 P.M.
5. A worker ships 25 boxes each day. Each box contains 3 shipping labels. The inventory has 500 shipping labels. How many days will it take to use the inventory of shipping labels? Round to the nearest whole.
- A. 7 days
- B. 8 days
- C. 20 days
- D. 6 days
Correct answer: A
Rationale: To find out how many days it will take to use the 500 shipping labels, multiply the number of labels used per day (25 boxes * 3 labels/box = 75 labels) by the total number of days the inventory will last (500 labels ÷ 75 labels/day = 6.67 days). Rounded to the nearest whole number, it will take 7 days to use the inventory of shipping labels. Choice B (8 days) is incorrect because the calculation yields 6.67 days, which rounds down to 6 days, making it an incorrect answer. Choice C (20 days) and Choice D (6 days) are also incorrect as they are not the nearest whole number to the correct answer of 7 days.
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