HESI A2
HESI A2 Math Practice
1. Solve for y if y = 3: 4y + 21 / y.
- A. 7.7
- B. 19
- C. 23/3
- D. 11
Correct answer: B
Rationale: To solve for y, substitute y = 3 into the equation: 4(3) + 21 / 3 = 12 + 7 = 19. Therefore, the correct answer is 19. Choice A (7.7) is incorrect as it does not result from the substitution. Choice C (23/3) is incorrect as it does not match the calculated value. Choice D (11) is incorrect, as it is not the result of the provided equation.
2. How many kilometers is equivalent to 200 meters?
- A. 50 kilometers
- B. 20 kilometers
- C. 12 kilometers
- D. 0.2 kilometers
Correct answer: D
Rationale: To convert meters to kilometers, divide the number of meters by 1000, as 1 kilometer is equal to 1000 meters. Therefore, 200 meters is equivalent to 200 / 1000 = 0.2 kilometers. Choices A, B, and C are incorrect because they do not correctly convert meters to kilometers. A provides an answer that would be correct if converting from kilometers to meters. B and C are much larger distances than what 200 meters represent.
3. What is the result of adding 12 + 2 + 312?
- A. 936
- B. 374.4
- C. 326
- D. 318.24
Correct answer: C
Rationale: To find the sum of 12 + 2 + 312, you simply need to add these numbers together. 12 + 2 = 14, and when you add 312 to 14, you get the correct total of 326. Therefore, the correct answer is C. Choice A (936), choice B (374.4), and choice D (318.24) are incorrect as they do not represent the correct sum of the given numbers.
4. What is the probability of rolling a 2 on a six-sided die?
- A. 1/6
- B. 1/4
- C. 1/3
- D. 1/2
Correct answer: A
Rationale: The correct answer is A: 1/6. A six-sided die has one face with a '2' out of six possible outcomes (numbers 1 to 6). Therefore, the probability of rolling a 2 is 1/6. Choices B, C, and D are incorrect because they do not reflect the specific probability of rolling a 2 on a six-sided die.
5. A lab needs 200ml of a 5% salt solution. They only have a 10% solution. How much 10% solution and water should be mixed?
- A. 100ml 10% solution, 100ml water
- B. 150ml 10% solution, 50ml water
- C. 160ml 10% solution, 40ml water
- D. 200ml 10% solution, 0ml water
Correct answer: B
Rationale: Rationale: 1. Let x be the volume of the 10% solution needed and y be the volume of water needed. 2. The total volume of the final solution is 200ml, so x + y = 200. 3. The concentration of the final solution is 5%, so the amount of salt in the final solution is 0.05 * 200 = 10g. 4. The amount of salt in the 10% solution is 0.1x, and the amount of salt in the water is 0, so the total amount of salt in the final solution is 0.1x. 5. Since the total amount of salt in the final solution is 10g, we have 0.1x = 10. 6. Solving for x, we get x = 100ml. 7. Substituting x =
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