ATI TEAS 7
Mometrix TEAS 7 science practice test
1. Imagine you have an element with atomic number 11 and mass number 23. How many neutrons does it have?
- A. 11
- B. 12
- C. 23
- D. 21
Correct answer: B
Rationale: - The atomic number (Z) of an element is the number of protons in its nucleus. In this case, the element has an atomic number of 11. - The mass number (A) of an element is the sum of its protons and neutrons. Given that the mass number is 23 and the atomic number is 11, we can calculate the number of neutrons by subtracting the atomic number from the mass number: Neutrons = Mass number - Atomic number = 23 - 11 = 12. - Therefore, the element with atomic number 11 and mass number 23 has 12 neutrons.
2. In the cardiovascular system, what does the term 'double circulation' refer to?
- A. The separation of oxygenated and deoxygenated blood flow within the heart.
- B. The regulation of blood pressure through vasoconstriction and vasodilation.
- C. The cyclic contraction and relaxation of the heart muscle.
- D. The existence of two separate circulatory pathways, one for the lungs and one for the body.
Correct answer: D
Rationale: The term 'double circulation' in the cardiovascular system refers to the existence of two separate circulatory pathways, one for the lungs (pulmonary circulation) and one for the body (systemic circulation). Oxygen-poor blood is pumped from the heart to the lungs for oxygenation, and then oxygen-rich blood is pumped from the lungs back to the heart to be circulated to the rest of the body. Choices A, B, and C are incorrect as they do not accurately describe the concept of 'double circulation.' Choice A refers to the separation of oxygenated and deoxygenated blood within the heart, choice B relates to blood pressure regulation mechanisms, and choice C describes the cardiac muscle's contraction and relaxation, none of which define 'double circulation' in the context of the cardiovascular system.
3. Salts like sodium iodide (NaI) and potassium chloride (KCl) use what type of bond?
- A. Ionic bonds
- B. Disulfide bridges
- C. Covalent bonds
- D. London dispersion forces
Correct answer: A
Rationale: Salts like sodium iodide (NaI) and potassium chloride (KCl) use ionic bonds. Ionic bonds are formed between atoms with significantly different electronegativities, leading to the transfer of electrons from one atom to another. In the case of NaI and KCl, sodium (Na) and potassium (K) are metals that easily lose electrons to become positively charged ions, while iodide (I) and chloride (Cl) are nonmetals that readily accept electrons to become negatively charged ions. The attraction between the oppositely charged ions forms the ionic bond, which holds the compound together in a lattice structure. Disulfide bridges (option B) are covalent bonds formed between sulfur atoms in proteins, not in salts. Covalent bonds (option C) involve the sharing of electrons between atoms and are typically seen in molecules, not ionic compounds like salts. London dispersion forces (option D) are weak intermolecular forces that occur between all types of molecules but are not the primary type of bond in salts like NaI and KCl.
4. Which valve allows blood flow from the right atrium into the right ventricle?
- A. Tricuspid valve
- B. Pulmonic valve
- C. Mitral valve
- D. Aortic valve
Correct answer: A
Rationale: The correct answer is the Tricuspid valve. This valve is located between the right atrium and the right ventricle in the heart. Its primary function is to facilitate the flow of blood from the right atrium into the right ventricle and to prevent the backflow of blood. The Pulmonic valve (choice B) is situated between the right ventricle and the pulmonary artery, not between the right atrium and ventricle, making it incorrect. The Mitral valve (choice C) is found between the left atrium and the left ventricle, not the right side, so it is incorrect. The Aortic valve (choice D) is positioned between the left ventricle and the aorta, not involved in the right atrium and ventricle connection, hence it is also incorrect.
5. Which type of wave does not require a medium for propagation?
- A. Transverse wave
- B. Longitudinal wave
- C. Mechanical wave
- D. Electromagnetic wave
Correct answer: D
Rationale: The correct answer is D, Electromagnetic wave. Electromagnetic waves do not require a medium for propagation because they consist of oscillating electric and magnetic fields that can travel through a vacuum. In contrast, transverse and longitudinal waves are mechanical waves that require a medium (solid, liquid, or gas) for propagation. Therefore, options A, B, and C are incorrect as they are all types of mechanical waves that necessitate a medium for transmission.
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