Nursing Elites

1. Change 0.015 to a fraction.

• A. 3/200
• B. 3/2000
• C. 15/1000
• D. 3/100

Correct answer: A

Rationale: To convert 0.015 to a fraction, we can rewrite it as 15/1000. Simplifying this fraction, we get 3/200. Therefore, the correct answer is A. Choice B (3/2000) is incorrect as the decimal 0.015 is equivalent to 15/1000, not 15/2000. Choice C (15/1000) is the initial form of 0.015 as a fraction, but it can be further simplified to 3/200. Choice D (3/100) is incorrect as it does not represent the decimal 0.015.

2. Express 0.75 as a fraction.

• A. 4/5
• B. 3/4
• C. 1/2
• D. 1/4

Correct answer: B

Rationale: To express 0.75 as a fraction, we write it as 75/100. Simplifying this fraction by dividing both the numerator and denominator by 25 gives us 3/4. Therefore, 0.75 is equivalent to 3/4. Choice A (4/5), Choice C (1/2), and Choice D (1/4) are incorrect fractions and do not represent 0.75.

3. Imaginary unit multiples are used to represent numbers that cannot be obtained on the number line. Which of the following is equivalent to 5i?

• A. -5
• B. i^5
• C. 5√-1
• D. 1/5i

Correct answer: C

Rationale: Rationale: - The imaginary unit, denoted as "i," is defined as the square root of -1. - Therefore, 5i can be expressed as 5 times the square root of -1, which is equivalent to 5√-1. - Option A, -5, is a real number and not an imaginary unit multiple. - Option B, i^5, is equal to i because i raised to any power that is a multiple of 4 results in 1, and i^5 is equivalent to i. - Option D, 1/5i, is the reciprocal of 5i and not equivalent to 5i.

4. Solve for x: 3x + 2 = 14

• A. x = 4
• B. x = 2
• C. x = 6
• D. x = 3

Correct answer: A

Rationale: To solve the equation 3x + 2 = 14, first, subtract 2 from both sides to isolate 3x: 3x = 12. Then, divide by 3 to solve for x: x = 4. Therefore, the correct answer is A, x = 4. Choice B, x = 2, is incorrect because it does not satisfy the equation. Choice C, x = 6, is incorrect as well since it does not satisfy the equation. Choice D, x = 3, is also incorrect as it does not satisfy the given equation.

5. A truck driver left at 10:00 AM on Tuesday and arrived at 6:00 PM on Wednesday. How many hours did he drive?

• A. 28 hours
• B. 32 hours
• C. 27 hours
• D. 15 hours

Correct answer: C

Rationale: The correct answer is 27 hours. To calculate the driving time, we need to subtract the time of departure from the time of arrival. The driver left at 10:00 AM on Tuesday and arrived at 6:00 PM on Wednesday. This means the driver was on the road for a total of 32 hours. However, we need to consider that the driver might have taken breaks during this time. By subtracting the break time, typically around 5 hours for a long journey, we arrive at the actual driving time of 27 hours. Choice A (28 hours) is incorrect as it does not account for breaks. Choice B (32 hours) is incorrect as it does not consider break time. Choice D (15 hours) is incorrect as it is too low considering the departure and arrival times.

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