Nursing Elites

1. Why do cells need to use exocytosis?

• A. To obtain energy
• B. To defend against invaders
• C. To remove waste products
• D. To undergo division

Correct answer: C

Rationale: Cells need to use exocytosis to remove waste products from the cell. Exocytosis is a process where cells release molecules or substances outside the cell by fusing vesicles with the cell membrane. This process is crucial for maintaining cellular homeostasis by efficiently eliminating waste materials. Choices A, B, and D are incorrect because exocytosis is specifically involved in the expulsion of molecules, not for obtaining energy, defending against invaders, or cell division.

2. The mixture of gases surrounding a planet is referred to as its ______.

• A. Atmosphere
• B. Stratosphere
• C. Biosphere
• D. Troposphere

Correct answer: A

Rationale: The mixture of gases surrounding a planet is referred to as its atmosphere. The atmosphere plays a crucial role in supporting life on Earth by providing oxygen, regulating carbon dioxide levels, and shielding the planet from harmful radiation. While the stratosphere, troposphere, and other layers are part of the atmosphere, the term 'atmosphere' encompasses the entire gaseous envelope surrounding a planet. The stratosphere, troposphere, mesosphere, thermosphere, and exosphere are specific layers within the atmosphere, each with distinct characteristics and functions.

3. Huntington’s disease is carried on the dominant allele. In a situation where two heterozygous parents have the disease, what percentage of their offspring are predicted to be disease-free?

• A. 0%
• B. 25%
• C. 50%
• D. 100%

Correct answer: B

Rationale: In this scenario, both parents are heterozygous for Huntington's disease, meaning each carries one dominant allele (representing the disease) and one recessive allele (representing no disease). When they have offspring, there is a 25% chance that each child will inherit two recessive alleles, making them disease-free. The Punnett square for two heterozygous parents (Hh x Hh) yields a 25% probability of offspring being homozygous recessive (hh) and therefore disease-free. Choice A (0%) is incorrect because there is a possibility of disease-free offspring. Choice C (50%) is incorrect as it represents the likelihood of being a carrier. Choice D (100%) is incorrect as all offspring will not be disease-free in this scenario.

4. Epithelial cells are:

• A. Polarized
• B. Neutral
• C. Larger than other cells
• D. None of the above

Correct answer: A

Rationale: Epithelial cells have a distinct top (apical) and bottom (basal) side, demonstrating polarity. This polarity is essential for their specialized functions, such as secretion, absorption, and barrier formation. Choice B, 'Neutral,' is incorrect as epithelial cells exhibit polarity. Choice C, 'Larger than other cells,' is incorrect as epithelial cells come in various sizes and are not specifically larger than other cell types. Choice D, 'None of the above,' is incorrect as epithelial cells are indeed polarized.

5. Cells reproduce by different processes, all of which fall into what two categories?

• A. Sexual reproduction and binary fission
• B. Sexual reproduction and asexual reproduction
• C. Asexual reproduction and binary fission
• D. Asexual reproduction and mitosis

Correct answer: B

Rationale: Cells reproduce through two main processes: 'sexual reproduction and asexual reproduction.' Sexual reproduction involves the fusion of gametes to produce offspring with genetic variation, while asexual reproduction involves the production of offspring genetically identical to the parent. Choice A is incorrect because binary fission is a form of asexual reproduction, not sexual reproduction. Choice C is incorrect because it combines two forms of asexual reproduction. Choice D is incorrect because mitosis is a specific type of cell division, not a form of reproduction involving the production of offspring.

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