Nursing Elites

1. A rectangular field has an area of 1452 square feet. If the length is three times the width, what is the width of the field?

• A. 22 feet
• B. 44 feet
• C. 242 feet
• D. 1452 feet

Correct answer: A

Rationale: To find the width of the rectangular field, use the formula for the area of a rectangle: A = length × width. Given that the length is three times the width, you have A = 3w × w. Substituting the given area, 1452 = 3w^2. Solving for w, you get 484 = w^2. Taking the square root gives ±22, but since the width must be positive, the width of the field is 22 feet. Choice B, 44 feet, is incorrect because it represents the length, not the width. Choice C, 242 feet, is incorrect as it is not a factor of the area. Choice D, 1452 feet, is incorrect as it represents the total area of the field, not the width.

2. Simplify the following expression: (3)(-4) + (3)(4) - 1

• A. -1
• B. 1
• C. 23
• D. 24

Correct answer: A

Rationale: To solve the expression, first calculate the multiplication: (3)(-4) = -12 and (3)(4) = 12. Then, substitute the results back into the expression: (-12) + 12 - 1 = -1. Therefore, the correct answer is A. Choices B, C, and D are incorrect as they do not result from the correct calculations of the given expression.

3. Given a double bar graph, which statement is true about the distributions of Group A and Group B?

• A. Group A is negatively skewed, Group B is normal.
• B. Group A is positively skewed, Group B is normal.
• C. Group A is positively skewed, Group B is neutral.
• D. Group A is normal, Group B is negatively skewed.

Correct answer: B

Rationale: The correct answer is B. In statistical terms, a positively skewed distribution means that the tail on the right side of the distribution is longer or fatter than the left side, indicating more high values. Therefore, Group A is positively skewed. Conversely, an approximately normal distribution, also known as a bell curve, is symmetrical with no skewness. Hence, Group B is normal. Choices A, C, and D are incorrect because they do not accurately describe the skewness of Group A and the normal distribution of Group B as depicted in a double bar graph.

4. A homeowner has hired two people to mow his lawn. If person A is able to mow the lawn in 2 hours by herself and person B is able to mow the lawn in 3 hours by himself, what is the amount of time it would take for both person A and B to mow the lawn together?

• A. 5 hours
• B. 2.5 hours
• C. 1.2 hours
• D. 1 hour

Correct answer: C

Rationale: To find the combined work rate, you add the individual work rates: 1/2 + 1/3 = 5/6. This means that together, they can mow 5/6 of the lawn per hour. To determine how long it would take for both A and B to mow the entire lawn, you take the reciprocal of 5/6, which gives you 6/5 or 1.2 hours. Therefore, it would take 1.2 hours for person A and person B to mow the lawn together. Choice A (5 hours) is incorrect because it does not consider the combined efficiency of both workers. Choice B (2.5 hours) is incorrect as it does not reflect the correct calculation based on the combined work rates of the two individuals. Choice D (1 hour) is incorrect as it doesn't consider the fact that the combined rate is less than the individual rate of person A alone, thus taking longer than 1 hour.

5. Jonathan pays a $65 monthly flat rate for his cell phone. He is charged $0.12 per minute for each minute used in a roaming area. Which of the following expressions represents his monthly bill for x roaming minutes?

• A. 65 + 0.12x
• B. 65x + 0.12
• C. 65.12x
• D. 65 + 0.12x

Correct answer: A

Rationale: The correct expression for Jonathan's monthly bill is 65 + 0.12x, where x represents the number of roaming minutes. The $65 monthly flat rate is added to the product of $0.12 per minute and the number of roaming minutes (x). Choice B is incorrect because it incorrectly multiplies the flat rate by x and adds the per-minute charge. Choice C is incorrect as it combines the flat rate and the per-minute charge into a single value. Choice D is incorrect as it incorrectly multiplies the flat rate by x and adds the per-minute charge separately.

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