Nursing Elites

1. A medication dosage is listed as 1/2 teaspoon. What is the equivalent dosage in milliliters (1 teaspoon = 5ml)?

• A. 1.25ml
• B. 2.5ml
• C. 3.75ml
• D. 5ml

Correct answer: B

Rationale: Rationale: Given that 1 teaspoon is equal to 5ml, and the medication dosage is listed as 1/2 teaspoon, we need to find half of 5ml. 1/2 of 5ml = 5ml / 2 = 2.5ml Therefore, the equivalent dosage in milliliters for 1/2 teaspoon is 2.5ml.

2. Percent Increase/Decrease: A medication dosage is increased by 20%. If the original dosage was 100mg, what is the new dosage?

• A. 80mg
• B. 100mg
• C. 120mg
• D. 140mg

Correct answer: C

Rationale: Calculate the increase in dosage: 100mg * 20% = 100mg * 0.20 = 20mg. Add the increase to the original dosage to find the new dosage: 100mg + 20mg = 120mg. Therefore, the new dosage is 120mg after a 20% increase from the original 100mg dosage. Choice A (80mg) is incorrect because it represents a decrease rather than an increase. Choice B (100mg) is the original dosage and does not account for the 20% increase. Choice D (140mg) is incorrect as it is the original dosage plus 40%, not the 20% increase specified.

3. A patient weighs 180 pounds. What is their weight in kilograms (1kg = 2.2lbs)?

• A. 68kg
• B. 75kg
• C. 82kg
• D. 90kg

Correct answer: C

Rationale: To convert pounds to kilograms, you need to divide the weight in pounds by the conversion factor of 2.2 (1kg = 2.2lbs). 180 pounds / 2.2 = 81.82 kg Rounded to the nearest whole number, the weight of 180 pounds is approximately 82kg. Therefore, the correct answer is 82kg, which is option C. Option B (75kg) is not correct as it is significantly lower than the calculated value. Options A (68kg) and D (90kg) are also incorrect as they do not match the converted weight of 180 pounds.

4. A runner leaves at 7:45 for a morning run at an average speed of 6 mph and returns at 10:00. How many miles did he run?

• A. 11.5 miles
• B. 14.5 miles
• C. 12 miles
• D. 13.5 miles

Correct answer: D

Rationale: The runner left at 7:45 and returned at 10:00, which means he ran for 2 hours and 15 minutes (10:00 - 7:45). At an average speed of 6 mph, in 2.25 hours, he would have covered 6 mph * 2.25 hours = 13.5 miles. Therefore, the correct answer is 13.5 miles. Choices A, B, and C are incorrect because they incorrectly calculate the distance based on the time and speed provided in the question.

5. A researcher is collecting data on patient satisfaction. Out of 150 patients surveyed, 120 reported being satisfied with their care. What percentage of the patients were satisfied?

• A. 80%
• B. 75%
• C. 85%
• D. 90%

Correct answer: A

Rationale: To find the percentage of satisfied patients, divide the number of satisfied patients by the total number of patients surveyed and multiply by 100. In this case, 120 (satisfied patients) ÷ 150 (total patients surveyed) x 100 = 80%. Therefore, 80% of the patients were satisfied. Choice B (75%), C (85%), and D (90%) are incorrect percentages as the actual percentage of satisfied patients is 80%.

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