Nursing Elites

1. A diabetic patient's blood sugar is 180mg/dL. Their usual insulin dose is 1 unit per 40mg/dL above 100mg/dL. How much insulin should be administered?

• A. 2 units
• B. 3 units
• C. 4 units
• D. 5 units

Correct answer: B

Rationale: Rationale: 1. Calculate the excess blood sugar above 100mg/dL: 180mg/dL - 100mg/dL = 80mg/dL. 2. Determine the insulin dose based on the patient's usual insulin dose: 80mg/dL / 40mg/dL = 2 units. 3. Add the calculated insulin dose to the patient's usual insulin dose: 1 unit (usual dose) + 2 units (calculated dose) = 3 units. Therefore, the correct answer is 3 units of insulin should be administered to the diabetic patient with a blood sugar level of 180mg/dL.

2. Add: 1.332 + 0.067

• A. 1.399
• B. 1.4
• C. 1.402
• D. 1.5

Correct answer: A

Rationale: To find the sum of 1.332 and 0.067, add the two numbers correctly: 1.332 + 0.067 = 1.399. Therefore, the correct answer is A. Choice B (1.4) is incorrect because it rounds down the sum, not considering the precise value. Choice C (1.402) is incorrect as it results from adding 1.332 and 0.070 instead of 0.067. Choice D (1.5) is not the correct sum of the given numbers.

3. A patient's weight is measured as 75 kilograms. What is their weight in pounds?

• A. 132 pounds
• B. 150 pounds
• C. 110 pounds
• D. 85 pounds

Correct answer: B

Rationale: Rationale: To convert kilograms to pounds, you can use the conversion factor 1 kilogram is approximately equal to 2.20462 pounds. Therefore, to convert 75 kilograms to pounds: 75 kilograms * 2.20462 pounds/kilogram ≈ 165.3475 pounds Rounded to the nearest whole number, the patient's weight of 75 kilograms is approximately 165 pounds. Among the given options, the closest weight in pounds to 165 is 150 pounds (option B).

4. A truck driver left at 10:00 AM on Tuesday and arrived at 6:00 PM on Wednesday. How many hours did he drive?

• A. 28 hours
• B. 32 hours
• C. 27 hours
• D. 15 hours

Correct answer: C

Rationale: The correct answer is 27 hours. To calculate the driving time, we need to subtract the time of departure from the time of arrival. The driver left at 10:00 AM on Tuesday and arrived at 6:00 PM on Wednesday. This means the driver was on the road for a total of 32 hours. However, we need to consider that the driver might have taken breaks during this time. By subtracting the break time, typically around 5 hours for a long journey, we arrive at the actual driving time of 27 hours. Choice A (28 hours) is incorrect as it does not account for breaks. Choice B (32 hours) is incorrect as it does not consider break time. Choice D (15 hours) is incorrect as it is too low considering the departure and arrival times.

5. Solve the proportion (find the value of x): 9:14 = x:56.

• A. x = 14
• B. x = 25
• C. x = 36
• D. x = 42

Correct answer: C

Rationale: To solve the proportion 9:14 = x:56, you can cross multiply to get 9 * 56 = 14 * x. This simplifies to 504 = 14x. Dividing by 14 on both sides gives x = 36. Therefore, the value of x in the proportion is 36. Choice A, x = 14, is incorrect as it does not satisfy the proportion equation. Choice B, x = 25, is incorrect as it is not the value that makes the proportion true. Choice D, x = 42, is incorrect as it does not correctly satisfy the proportion equation.

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