a farmer wants to plant trees at the outside boundaries of his rectangular field of dimensions 650 meters 780 meters each tree requires 5 meter of fr
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HESI A2

HESI A2 Math Practice Exam

1. A farmer wants to plant trees at the outside boundaries of his rectangular field with dimensions 650 meters × 780 meters. Each tree requires 5 meters of free space all around it from the stem. How much free area will be left?

Correct answer: A

Rationale: To calculate the area taken by the trees, we need to account for the space each tree requires. Each tree needs 5 meters of free space all around it, totaling 10 meters added to each dimension. Therefore, the new dimensions of the field are (650-10) meters by (780-10) meters. Calculating the area of the new field: (640m × 770m = 492,800m²). To find the free area remaining, subtract the new field's area from the original field's area: 507,000m² - 492,800m² = 14,200m². Therefore, the free area left after planting the trees is 14,200m². Choice A is the correct answer as it represents the free area left after planting the trees.

2. A female ran a 24-mile course. Her first 6 miles she ran in 1 hour. The second set of 6 miles in 1.2 hours. The third set of 6 miles in 1.5 hours. The fourth set of 6 miles in 1.6 hours. How long did it take her to complete the course?

Correct answer: B

Rationale: To find the total time, add the times for each set of 6 miles: 1 + 1.2 + 1.5 + 1.6 = 5.3 hours. Therefore, it took her 5.3 hours to complete the 24-mile course. Choice A, 5 hours, is incorrect because the total time is slightly more than that. Choice C, 4 hours, is incorrect as it doesn't account for the total time taken. Choice D, 6 hours, is incorrect as it's an overestimation of the actual time taken.

3. What is the result of the expression 47/57 + 65/75?

Correct answer: A

Rationale: To add fractions, you need a common denominator. In this case, the common denominator is 57 * 75 = 4275. So, (47*75 + 65*57) / 4275 = (3525 + 3705) / 4275 = 7230 / 4275. Simplifying this fraction gives 1 23/35. Choice B: 2 1/3 is incorrect as the correct result is not a mixed number. Choice C: 1 2/3 is incorrect as it does not match the simplified result of the expression. Choice D: 1 5/6 is incorrect as it is a different value from the correct result obtained by adding the fractions.

4. Add 7/8 + 9/10 + 6/5. Express the result as a mixed number.

Correct answer: A

Rationale: To add fractions, find a common denominator, which in this case is 40. Convert each fraction to have the common denominator: 7/8 = 35/40, 9/10 = 36/40, and 6/5 = 48/40. Add these fractions to get 119/40. Simplify this improper fraction to a mixed number, which is 3 & 39/40. Choice B and C are incorrect as they do not represent the sum of the fractions. Choice D is incorrect; the whole number part should be 3, not 2.

5. A worker's schedule is written in military time, and shows their shift is from 1500 to 0100. When will they get off work?

Correct answer: B

Rationale: When converting military time, 0100 actually corresponds to 1:00 AM the next day. Choice A is incorrect as 'a little bit after midnight' is vague and not a specific time. Choice C is incorrect as it is after the worker's shift ends. Choice D is incorrect as it is before the worker's shift ends.

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