Nursing Elites

1. What is the balanced chemical equation for the reaction between sodium and chlorine to form sodium chloride?

• A. Na + Cl2 -> NaCl
• B. 2Na + Cl2 -> 2NaCl
• C. Na2 + Cl -> 2NaCl
• D. Na + 2Cl -> NaCl2

Correct answer: B

Rationale: In a balanced chemical equation, the number of atoms of each element must be the same on both sides of the equation. When sodium (Na) reacts with chlorine (Cl2) to form sodium chloride (NaCl), we need to ensure the equation is balanced. There are 2 chlorine atoms in Cl2; hence, we need 2 sodium atoms on the left side to balance it. Therefore, the balanced chemical equation is 2Na + Cl2 -> 2NaCl. Choice A is incorrect because it does not have the correct coefficients to balance the equation. Choice C is incorrect as it incorrectly represents the formula of sodium. Choice D is incorrect as it forms NaCl2, which is not the correct compound formed in this reaction.

2. Which of the following correctly lists the normal blood flow through the heart?

• A. Left ventricle, left atrium, body, right ventricle, right atrium, lungs
• B. Left atrium, left ventricle, lungs, right atrium, right ventricle, body
• C. Right atrium, right ventricle, lungs, left atrium, left ventricle, body
• D. Right ventricle, right atrium, body, left atrium, left ventricle, lungs

Correct answer: B

Rationale: The correct order of normal blood flow through the heart is as follows: from the body, blood flows into the right atrium, then to the right ventricle, followed by the lungs through the pulmonary artery for oxygenation. Oxygenated blood then returns to the heart through the pulmonary veins into the left atrium, then moves into the left ventricle before being pumped out to the body. Choice B correctly depicts this sequential flow of blood through the heart. Choices A, C, and D are incorrect as they do not follow the typical path of blood flow through the heart.

3. In which medium does light propagate at its highest speed?

• A. Air
• B. Water
• C. Glass
• D. Diamond

Correct answer: A

Rationale: Light travels at its highest speed in a vacuum. However, among the options provided, air is the closest medium to a vacuum, making it the correct answer. In general, light travels slower in denser mediums due to interactions with atoms and molecules in the medium. Water, glass, and diamond are denser mediums compared to air, causing light to propagate at slower speeds in these materials, hence making them incorrect choices.

4. At the peak of its trajectory, what force is acting on a ball thrown upwards?

• A. Gravity only
• B. Gravity and air resistance only
• C. Neither gravity nor air resistance
• D. All of the above

Correct answer: A

Rationale: At the peak of its trajectory, the ball momentarily stops moving upwards before it starts to fall back down. At this point, the only force acting on the ball is gravity, pulling it back towards the ground. Air resistance is negligible at the peak of the trajectory as the ball is momentarily stationary. Therefore, the correct answer is 'Gravity only.' Choices B, C, and D are incorrect. Option B is incorrect because air resistance is minimal when the ball is at its highest point and its velocity is nearly zero. Option C is incorrect as gravity is the only significant force acting on the ball at that instant. Option D is incorrect since air resistance is not a significant factor at the peak of the trajectory.

5. Which of the following cations is found at the center of a heme?

• A. Cr (III)
• B. Cu (II)
• C. Iron (II)
• D. Iron (III)

Correct answer: C

Rationale: The correct answer is Iron (II) (Fe2+), which is the cation found at the center of a heme group. Heme contains an iron (II) ion that is coordinated within the porphyrin ring structure. This iron ion is crucial for the function of heme in binding and transporting oxygen in hemoglobin and myoglobin. Choice A (Cr (III)) is incorrect as chromium is not typically found at the center of a heme group. Choice B (Cu (II)) is incorrect as copper is not the cation typically present in heme. Choice D (Iron (III)) is also incorrect as heme predominantly contains iron (II) at its center, not iron (III).

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