Nursing Elites

1. Which of these is not an example of a lipid?

• A. Butter
• B. Wax
• C. Canola oil
• D. Honey

Correct answer: D

Rationale: Honey is not an example of a lipid because lipids are fat-related molecules that are insoluble in water, while honey is a natural sweet substance made by bees and primarily consists of sugars such as glucose and fructose. Butter, wax, and canola oil are examples of lipids as they are all composed of fat-related molecules that do not dissolve in water.

2. Which of the following is true of Glycolysis?

• A. It requires the absence of Oxygen
• B. It occurs in the presence of Oxygen
• C. It is the final step of fermentation
• D. It is the final step of anaerobic respiration

Correct answer: B

Rationale: Glycolysis is the first step in cellular respiration and can occur in both aerobic (presence of oxygen) and anaerobic (absence of oxygen) conditions. In aerobic respiration, glycolysis takes place in the presence of oxygen and continues with the Krebs cycle and the electron transport chain. So, glycolysis does not require the absence of oxygen but can occur in its presence as part of the overall process of aerobic respiration. Choice A is incorrect because glycolysis can occur in the presence of oxygen. Choice C is incorrect because glycolysis is not the final step of fermentation; it is the initial step. Choice D is incorrect because glycolysis is not the final step of anaerobic respiration; it is the first step, followed by further processes to complete anaerobic respiration.

3. Huntington’s disease is carried on the dominant allele. In a situation where two heterozygous parents have the disease, what percentage of their offspring are predicted to be disease-free?

• A. 0%
• B. 25%
• C. 50%
• D. 100%

Correct answer: B

Rationale: In this scenario, both parents are heterozygous for Huntington's disease, meaning each carries one dominant allele (representing the disease) and one recessive allele (representing no disease). When they have offspring, there is a 25% chance that each child will inherit two recessive alleles, making them disease-free. The Punnett square for two heterozygous parents (Hh x Hh) yields a 25% probability of offspring being homozygous recessive (hh) and therefore disease-free. Choice A (0%) is incorrect because there is a possibility of disease-free offspring. Choice C (50%) is incorrect as it represents the likelihood of being a carrier. Choice D (100%) is incorrect as all offspring will not be disease-free in this scenario.

4. Why do we perceive chlorophyll as green?

• A. It absorbs yellow and blue light.
• B. It primarily absorbs green light.
• C. It fails to absorb green light.
• D. It primarily absorbs red light.

Correct answer: A

Rationale: Chlorophyll appears green to us because it primarily absorbs yellow and blue light while reflecting green light. The wavelengths of yellow and blue light are absorbed by chlorophyll for photosynthesis, which results in the green color we perceive. Choice B is incorrect because chlorophyll absorbs yellow and blue light, not green light. Choice C is incorrect because chlorophyll does absorb green light, but it also absorbs other wavelengths, primarily yellow and blue. Choice D is incorrect because chlorophyll primarily absorbs yellow and blue light, not red light.

5. Choose the two bases that have two carbon rings:

• A. Adenine
• B. Cytosine
• C. Thymine
• D. Guanine

Correct answer: A

Rationale: Adenine and guanine have two carbon rings and are known as purines. These bases are found in nucleic acids such as DNA and RNA. Adenine (option A) and guanine (option D) are the correct choices as they both have two carbon rings in their molecular structure. Cytosine (option B) and thymine (option C) have a single carbon ring each, making them incorrect choices for bases with two carbon rings.

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