Nursing Elites

1. Which names a final step in protein synthesis?

• A. DNA unzips.
• B. Amino acids bond.
• C. Transfer RNA bonds to messenger RNA.
• D. Messenger RNA moves to ribosomes.

Correct answer: B

Rationale: The final step in protein synthesis is when amino acids bond together to form a protein chain. This process occurs during translation, where transfer RNA (tRNA) brings specific amino acids to the ribosome, and the ribosome catalyzes the formation of peptide bonds between the amino acids. This step ultimately leads to the synthesis of a complete protein based on the instructions from messenger RNA (mRNA). Choice A ('DNA unzips') is incorrect as it refers to the initiation of transcription, not the final step of protein synthesis. Choice C ('Transfer RNA bonds to messenger RNA') is incorrect as it describes the process of translation initiation rather than the final step. Choice D ('Messenger RNA moves to ribosomes') is also incorrect as mRNA is already present at the ribosomes throughout the translation process, not just in the final step.

2. Which of the following is the structure of the male reproductive system that stores spermatozoa during the maturation process?

• A. vas deferens
• B. scrotum
• C. epididymis
• D. testicular artery

Correct answer: C

Rationale: The epididymis is the structure of the male reproductive system that stores spermatozoa during the maturation process. Sperm cells produced in the testes move to the epididymis, where they mature and become motile before being ejaculated. The vas deferens is responsible for transporting mature sperm to the urethra during ejaculation, the scrotum holds the testes and helps regulate their temperature for sperm production, and the testicular artery supplies blood to the testes. Therefore, choices A, B, and D are incorrect as they do not play a direct role in storing spermatozoa during the maturation process.

3. What happens to glucose during glycolysis?

• A. Its energy is entirely lost.
• B. It splits into molecules of pyruvic acid.
• C. It is stored in NADH.
• D. It joins with molecules of citric acid.

Correct answer: B

Rationale: During glycolysis, glucose undergoes a series of enzymatic reactions in the cytoplasm of the cell, resulting in its breakdown into two molecules of pyruvic acid. This process also generates ATP and NADH as energy carriers. Choice A is incorrect because glucose is not entirely lost, but rather converted into other molecules. Choice C is incorrect because NADH is a product of glycolysis, not a storage form for glucose. Choice D is incorrect as glucose does not join with molecules of citric acid during glycolysis, but rather in subsequent stages of cellular respiration.

4. How many chromosomes do sperm and egg produce in meiosis?

• A. 46
• B. 23
• C. 45
• D. 24

Correct answer: B

Rationale: Sperm and egg cells undergo meiosis to form gametes with half the number of chromosomes found in somatic cells. Each sperm and egg cell produces 23 chromosomes through meiosis. Choice A is incorrect because 46 chromosomes represent the diploid number found in somatic cells. Choice C is incorrect as it is an uncommon number for chromosome production in human gametes. Choice D is incorrect as the total number of chromosomes in sperm or egg cells is 23, not 24.

5. A student was asked to count birds in a given location over a 24-hour period. Which count would make their data most valid?

• A. Count birds at one feeder every 6 hours.
• B. Count birds at three feeders at noon and 6:00 P.M.
• C. Count birds at one feeder at noon and 6:00 P.M.
• D. Count birds at three feeders every 6 hours.

Correct answer: C

Rationale: Counting birds at one feeder at consistent time intervals (noon and 6:00 P.M.) over a 24-hour period ensures that the data collected are evenly distributed and provide a more accurate representation of the bird population in that location throughout the day. This method allows for observations during different times of the day, capturing potential variations in bird activity and distribution. Choice A is not as effective as it lacks observations at different times of the day, potentially missing variations in bird behavior. Choice B involves multiple locations and times, which could introduce more variables and make it harder to analyze the data accurately. Choice D, counting birds at three feeders every 6 hours, may provide too frequent data points and not cover all significant time intervals for observing bird activity.

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