HESI A2
HESI A2 Physics Practice Test
1. When a dielectric material is inserted between the plates of a charged capacitor, what will happen to the capacitance?
- A. Increase
- B. Decrease
- C. Remain the same
- D. Become unpredictable
Correct answer: A
Rationale: When a dielectric material is inserted between the plates of a charged capacitor, the capacitance will increase. This is because the presence of a dielectric material reduces the electric field between the plates, allowing more charge to be stored for a given voltage, thus increasing the capacitance. Choice B is incorrect because adding a dielectric material increases capacitance. Choice C is incorrect because capacitance changes when a dielectric is added. Choice D is incorrect because the effect of a dielectric on capacitance is predictable.
2. A wave moves through its medium at 20 m/s with a wavelength of 4 m. What is the frequency of the wave?
- A. 5 s−1
- B. 16 s−1
- C. 24 s−1
- D. 80 s−1
Correct answer: C
Rationale: The formula to calculate the frequency of a wave is given by:
3. How might the energy use of an appliance be expressed?
- A. Power = energy × time
- B. Time + energy = power
- C. Energy = power × time
- D. Energy/power = time
Correct answer: C
Rationale: The energy use of an appliance can be expressed using the formula Energy = Power × Time. In this formula, Energy represents the amount of electricity consumed by the appliance, Power indicates the rate at which the appliance uses electricity (measured in watts), and Time represents the duration for which the appliance is being used (measured in hours). By multiplying the power rating of the appliance by the time it is in use, one can calculate the total energy consumed. Option C is the correct choice because it accurately represents the relationship between power, time, and energy. Choices A, B, and D present incorrect representations of the relationship between energy, power, and time, making them wrong answers.
4. If a force of 12 kg stretches a spring by 3 cm, how far will the spring stretch when a force of 30 kg is applied?
- A. 6 cm
- B. 7.5 cm
- C. 9 cm
- D. 10.5 cm
Correct answer: B
Rationale: The extension of a spring is directly proportional to the force applied. In this case, the force increases from 12 kg to 30 kg, which is a 2.5 times increase. Therefore, the extension of the spring will also increase by 2.5 times. Given that the spring stretches 3 cm with a force of 12 kg, multiplying 3 cm by 2.5 gives us the extension of the spring when a force of 30 kg is applied, which equals 7.5 cm. Therefore, the correct answer is 7.5 cm. Choice A, 6 cm, is incorrect because it does not account for the proportional increase in force. Choice C, 9 cm, and Choice D, 10.5 cm, are incorrect as they overestimate the extension of the spring by not considering the direct proportionality between force and extension.
5. Archimedes' principle explains the ability to control buoyancy, allowing:
- A. Objects to sink regardless of density differences.
- B. Airplanes to generate lift for flight.
- C. Submarines to adjust their buoyancy for submergence and resurfacing.
- D. Helium balloons to overcome gravity and float.
Correct answer: C
Rationale: Archimedes' principle states that the upward buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. Submarines control their buoyancy by adjusting the volume of water they displace, which allows them to submerge and resurface. Choice C is correct because it directly relates to the principle of buoyancy and how submarines utilize it. Choices A, B, and D are incorrect because they do not accurately reflect the application of Archimedes' principle in controlling buoyancy for submergence and resurfacing.
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