Nursing Elites

1. What is the process of removing waste products from the cell called?

• A. Exocytosis
• B. Endocytosis
• C. Phagocytosis
• D. Pinocytosis

Correct answer: A

Rationale: A) Exocytosis is the process by which cells expel waste products or other substances by fusing a vesicle containing the waste with the cell membrane, releasing its contents outside the cell. This process is essential for maintaining cellular homeostasis by removing waste products from the cell. B) Endocytosis is the process by which cells take in substances by engulfing them in a vesicle formed from the cell membrane. This process is the opposite of exocytosis and is used to bring substances into the cell. C) Phagocytosis is a type of endocytosis where cells engulf solid particles or other cells to form a vesicle called a phagosome. This process is used by immune cells to engulf and destroy pathogens. D) Pinocytosis is a type of endocytosis where cells engulf fluids and dissolved solutes. This process allows cells to take in nutrients.

2. What is the significance of the nuclear envelope breaking down during mitosis?

• A. It allows the chromosomes to condense and become visible.
• B. It allows the spindle apparatus to form and attach to the chromosomes.
• C. It allows the sister chromatids to separate.
• D. It allows the nuclear material to be evenly distributed to the daughter cells.

Correct answer: B

Rationale: A) The breakdown of the nuclear envelope does not directly cause the chromosomes to condense and become visible. Chromosome condensation is a separate process that occurs before mitosis begins. B) The breakdown of the nuclear envelope is crucial for the formation of the spindle apparatus, a structure made of microtubules that helps separate the chromosomes during cell division. The spindle apparatus attaches to the chromosomes and helps move them to opposite poles of the cell. C) The separation of sister chromatids occurs during anaphase, which is facilitated by the spindle apparatus. The breakdown of the nuclear envelope is not directly involved in this process. D) The even distribution of nuclear material to daughter cells is achieved through the movement of chromosomes by the spindle apparatus, which is made possible by the breakdown of the nuclear envelope.

3. What is the SI unit of measurement for work?

• A. Newton-meter (N·m)
• B. Joule (J)
• C. Watt (W)
• D. Meter per second (m/s)

Correct answer: B

Rationale: The correct answer is B: Joule (J). Work is defined as the amount of energy transferred by a force acting through a distance. The Joule is the unit used to measure this energy transfer. Choice A, Newton-meter (N·m), is the unit for torque, not work. Choice C, Watt (W), is the unit of power, not work. Choice D, Meter per second (m/s), is a unit for speed or velocity and is not related to work.

4. Four different groups of the same species of peas are grown and exposed to differing levels of sunlight, water, and fertilizer as documented in the table below. The data in the water and fertilizer columns indicate how many times the peas are watered or fertilized per week, respectively. Group 2 is the only group that withered. What is a reasonable explanation for this occurrence? Group Sunlight Water Fertilizer 1 partial sun 4 mL/hr 1 2 full sun 7 mL/hr 1 3 no sun 14 mL/hr 2 4 partial sun 3 mL/hr 2

• A. Insects gnawed away at the stem of the plant.
• B. The roots rotted due to poor drainage.
• C. The soil type had nutritional deficiencies.
• D. This species of peas does not thrive in full sunlight.

Correct answer: D

Rationale: Group 2, the only group that withered, was exposed to full sun. This suggests that the species of peas being studied does not thrive in full sunlight, leading to its deterioration compared to the other groups with different light exposures. Choices A, B, and C are not the correct explanations for the withering of Group 2. There is no mention of insects in the stem, poor drainage, or soil nutritional deficiencies in the scenario provided. The key factor that sets Group 2 apart from the others is the full sunlight exposure, indicating that the species of peas is not suited for such conditions.

5. Which process allows for the movement of large molecules, such as proteins and polysaccharides, across the cell membrane?

• A. Endocytosis
• B. Exocytosis
• C. Active transport
• D. Facilitated diffusion

Correct answer: A

Rationale: Endocytosis is the process by which cells engulf large molecules or particles by wrapping the cell membrane around them to form a vesicle that is brought into the cell. This mechanism facilitates the movement of large molecules like proteins and polysaccharides across the cell membrane. Exocytosis involves the release of large molecules or particles from the cell, opposite to the scenario described in the question. Active transport requires energy to move molecules against their concentration gradient and is not primarily used for transporting proteins and polysaccharides. Facilitated diffusion entails the movement of molecules aided by transport proteins but is not the primary mechanism for transporting large molecules such as proteins and polysaccharides.

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