what is an alloy in which another metal is dissolved in mercury hg called

HESI A2

Chemistry HESI A2 Practice Test

1. What is an alloy in which another metal is dissolved in mercury (Hg) called?

A. Electrum
B. Amalgam
C. Solder
D. Bronze

Correct answer: B

Rationale: An amalgam is a type of alloy where another metal is dissolved in mercury (Hg). This process forms a unique mixture that has various applications in dentistry, chemistry, and other fields. Electrum is a natural alloy of gold and silver, solder is a metal alloy used to join other metals together, and bronze is a copper-tin alloy. Therefore, the correct answer is B - Amalgam.

2. A salt solution has a molarity of 5 M. How many moles of this salt are present in 0 L of this solution?

A. 0
B. 1.5
C. 2
D. 3

Correct answer: A

Rationale: Molarity is defined as the number of moles of solute per liter of solution. A molarity of 5 M indicates there are 5 moles of salt in 1 liter of the solution. Since the volume of the solution is 0 liters, multiplying the molarity by 0 liters results in 0 moles of salt (5 moles/L x 0 L = 0 moles). Therefore, the correct answer is 0. Option B, 1.5, is incorrect because it doesn't consider the volume being 0 liters. Options C and D, 2 and 3 respectively, are also incorrect as they do not account for the zero volume of the solution. Hence, there are no moles of salt present in 0 liters of the solution.

3. Balance this equation: Zn + HCl â†’ ZnCl + H2.

A. Zn + 2HCl â†’ ZnCl + H2
B. Zn + HCl â†’ 2ZnCl + H2
C. 2Zn + 2HCl â†’ 2ZnCl + H2
D. Zn + 4HCl â†’ ZnCl + H2

Correct answer: C

Rationale: The given unbalanced equation is Zn + HCl â†’ ZnCl + H2. To balance it, we need to have equal atoms on both sides of the equation. The balanced equation is 2Zn + 2HCl â†’ 2ZnCl + H2. This balanced equation shows that two atoms of Zn combine with two molecules of HCl to form two molecules of ZnCl and one molecule of H2. Choice A is incorrect because it does not balance the equation. Choice B is incorrect as it does not have the same number of atoms on both sides. Choice D is incorrect because it does not balance the equation properly, resulting in an unequal number of atoms on both sides.

4. You contain two odorous gases in vials with porous plugs. Gas A has twice the mass of Gas B. Which observation is most likely?

A. You will smell Gas A before you smell Gas B.
B. You will smell Gas B before you smell Gas A.
C. You will smell Gas A but not Gas B.
D. You will smell Gas B but not Gas A.

Correct answer: A

Rationale: The rate of effusion of a gas is inversely proportional to the square root of its molar mass. Since Gas A has twice the mass of Gas B, Gas A will effuse more slowly than Gas B. Therefore, you will likely smell Gas A before you smell Gas B as Gas A will escape and diffuse through the porous plug at a slower rate compared to Gas B. Choice A is correct because Gas A, with its higher molar mass, will take longer to effuse through the porous plug, causing you to smell it first. Choices B, C, and D are incorrect as they do not consider the relationship between molar mass and effusion rate.

5. What are the three types of radiation?

A. Alpha, beta, gamma
B. Alpha, beta, delta
C. Gamma, delta, epsilon
D. Beta, gamma, epsilon

Correct answer: A

Rationale: The correct answer is Alpha, beta, gamma. Alpha radiation consists of helium nuclei, beta radiation comprises electrons or positrons, and gamma radiation is high-energy electromagnetic radiation. Choice B, delta, is incorrect as delta is not a type of radiation. Choice C, gamma, delta, epsilon, and Choice D, beta, gamma, epsilon, are incorrect as they do not include the three standard types of radiation.