ATI TEAS 7
ATI TEAS Science Questions
1. What is a monohybrid cross, and what is the ratio of dominant to recessive gene manifestation?
- A. A cross involving two traits, 9:3:3:1
- B. A cross involving one trait, 3:1
- C. A cross involving two traits, 1:2:1
- D. A cross involving one trait, 1:1
Correct answer: B
Rationale: A monohybrid cross is a genetic cross involving one trait. The ratio of dominant to recessive gene manifestation in the offspring is typically 3:1 when both parents are heterozygous. This ratio is the genotypic ratio, not just the phenotype ratio, where the dominant allele is present in 3 out of 4 offspring, and the recessive allele is present in 1 out of 4 offspring. Choice A is incorrect because it describes a dihybrid cross ratio. Choice C is incorrect as it represents the genotypic ratio for a monohybrid cross involving incomplete dominance. Choice D is incorrect as it does not reflect the typical ratio for a monohybrid cross.
2. The Gram stain is a differential staining technique used to classify bacteria based on their cell wall composition. Gram-positive bacteria appear
- A. Pink
- B. Blue
- C. Red
- D. Purple
Correct answer: D
Rationale: The Gram stain is a differential staining technique that categorizes bacteria into two groups based on their cell wall composition: Gram-positive and Gram-negative. Gram-positive bacteria have a thick layer of peptidoglycan in their cell walls, which retains the crystal violet stain used in the Gram staining procedure. Consequently, Gram-positive bacteria appear purple under the microscope after staining. On the other hand, Gram-negative bacteria possess a thinner peptidoglycan layer and an outer membrane that can be penetrated by the counterstain safranin, leading them to appear pink or red. Blue is not typically used to describe the color of bacteria in a Gram stain, making it an incorrect choice.
3. What is the process of converting simple sugars into complex carbohydrates called?
- A. Glycolysis
- B. Gluconeogenesis
- C. Krebs cycle
- D. Oxidative phosphorylation
Correct answer: B
Rationale: Gluconeogenesis is the correct answer. It is the process of synthesizing glucose from non-carbohydrate sources, such as amino acids or glycerol. A) Glycolysis is the process of breaking down glucose into pyruvate to produce energy. C) The Krebs cycle, also known as the citric acid cycle, generates energy through the oxidation of acetyl-CoA derived from carbohydrates, fats, and proteins. D) Oxidative phosphorylation is the final stage of cellular respiration where ATP is produced using energy derived from the electron transport chain. Therefore, choices A, C, and D are not the processes involved in converting simple sugars into complex carbohydrates.
4. How are sister chromatids distinguished from homologous chromosomes in meiosis I?
- A. Sister chromatids share the same centromere, while homologous chromosomes have different centromeres.
- B. Sister chromatids have identical DNA sequences, while homologous chromosomes have slightly different sequences due to crossing over.
- C. Sister chromatids repel each other, while homologous chromosomes attract each other during synapsis.
- D. Sister chromatids separate during anaphase I, while homologous chromosomes separate during anaphase II.
Correct answer: B
Rationale: In meiosis I, sister chromatids are exact copies of each other, containing identical DNA sequences. On the other hand, homologous chromosomes are pairs of chromosomes, with one inherited from each parent, and they can have different versions of genes due to genetic recombination during crossing over in prophase I. Choice A is incorrect because homologous chromosomes naturally have different centromeres. Choice C is incorrect as sister chromatids and homologous chromosomes do not exhibit repulsion or attraction during synapsis. Choice D is incorrect as sister chromatids separate during anaphase II, not anaphase I, while homologous chromosomes separate during anaphase I.
5. In a study where fish are fed different amounts of food daily for four weeks in separate tanks, with fish weight measured weekly, what is the dependent variable?
- A. Weight of the fish
- B. Type of food used
- C. Number of fish tanks
- D. Frequency of feedings
Correct answer: A
Rationale: The weight of the fish is the dependent variable in this study because it is the outcome being measured in response to the varying feeding amounts. The weight of the fish changes based on the feeding regimen, making it the dependent variable. The type of food used (choice B), number of fish tanks (choice C), and frequency of feedings (choice D) are not the dependent variables in this study. These factors may be independent variables that are manipulated or controlled in the experiment to observe their impact on the dependent variable, which is the weight of the fish.
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