Nursing Elites

1. University X requires some of its nursing students to take an exam before being admitted into the nursing program. In this year's class, half of the nursing students were required to take the exam, and three-fifths of those who took the exam passed. If this year's class has 200 students, how many students passed the exam?

• A. 120
• B. 100
• C. 60
• D. 50

Correct answer: C

Rationale: If the incoming class has 200 students, then half of those students were required to take the exam. (200)(1/2) = 100. So 100 students took the exam, but only three-fifths of that 100 passed the exam. (100)(3/5) = 60. Therefore, 60 students passed the exam. The correct answer is 60. Choice A is incorrect as it miscalculates the number of students who passed the exam. Choice B is incorrect as it does not consider the passing rate of the exam. Choice D is incorrect as it is much lower than the correct answer.

2. Simplify the expression below. Which of the following is correct? 3.45 * 0.53

• A. 1.8285
• B. 18.285
• C. 0.18285
• D. 182.85

Correct answer: A

Rationale: To solve 3.45 * 0.53, multiply the numbers to get 1.8285. Therefore, the correct answer is A. Choice B is incorrect because it incorrectly moves the decimal point. Choice C is incorrect as it is a fraction of the correct answer. Choice D is incorrect as it results from an error in moving the decimal point.

3. During week 1, Nurse Cameron works 5 shifts. During week 2, she worked twice as many shifts as she did in week 1. In week 3, she added 4 shifts to the number of shifts worked in week 2. Which equation describes the number of shifts Nurse Cameron worked in week 3?

• A. Shifts = (2)(5) + 4
• B. Shifts = (4)(5) + 2
• C. Shifts = 5 + 2 + 4
• D. Shifts = (5)(2)(4)

Correct answer: A

Rationale: During week 1, Nurse Cameron worked 5 shifts. In week 2, she worked twice as many shifts as in week 1, which is 10 shifts. In week 3, she added 4 shifts to the number of shifts worked in week 2. Therefore, the total shifts in week 3 can be calculated as (2)(5) + 4 = 10 + 4 = 14 shifts. Choice A correctly represents this calculation. Choices B, C, and D are incorrect because they do not accurately reflect the given scenario and the steps needed to find the total shifts in week 3.

4. What is the value of 0.0523 expressed as a fraction?

• A. 523/10000
• B. 523/1000
• C. 523/100
• D. 523/10

Correct answer: A

Rationale: To convert a decimal to a fraction, place the decimal value over the place value of the last digit. In this case, 0.0523 can be expressed as 523/10000 since the last digit is in the ten-thousandths place. Choice A is correct. Choices B, C, and D are incorrect because they represent different decimal values and do not match the correct conversion of 0.0523.

5. A car dealership’s commercials claim that this year’s models are 20% off the list price, plus they will pay the first 3 monthly payments. If a car is listed for $26,580, and the monthly payments are set at $250, what is the total potential savings?

• A. $1,282
• B. $5,566
• C. $6,066
• D. $20,514

Correct answer: C

Rationale: To calculate the total potential savings: First, find the 20% discount on the list price of $26,580: 0.20 × $26,580 = $5,316. Then, determine the savings over the first 3 months of payments: 3 months × $250/month = $750. Add the discount and the monthly payment savings to get the total potential savings: $5,316 + $750 = $6,066. Therefore, the correct answer is $6,066. Choice A, $1,282, is incorrect because it does not account for the total savings from both the discount and the monthly payments. Choice B, $5,566, is incorrect as it miscalculates the total savings by excluding the savings from the monthly payments. Choice D, $20,514, is incorrect as it does not consider the discount and only focuses on the list price.

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