Nursing Elites

1. University X requires some of its nursing students to take an exam before being admitted into the nursing program. In this year's class, half of the nursing students were required to take the exam, and three-fifths of those who took the exam passed. If this year's class has 200 students, how many students passed the exam?

• A. 120
• B. 100
• C. 60
• D. 50

Correct answer: C

Rationale: If the incoming class has 200 students, then half of those students were required to take the exam. (200)(1/2) = 100. So 100 students took the exam, but only three-fifths of that 100 passed the exam. (100)(3/5) = 60. Therefore, 60 students passed the exam. The correct answer is 60. Choice A is incorrect as it miscalculates the number of students who passed the exam. Choice B is incorrect as it does not consider the passing rate of the exam. Choice D is incorrect as it is much lower than the correct answer.

2. Four people split a bill. The first person pays for 1/3, the second person pays for 1/4, and the third person pays for 1/6. What fraction of the bill does the fourth person pay?

• A. 1/4
• B. 1/6
• C. 1/3
• D. 1/12

Correct answer: D

Rationale: To find out what fraction of the bill the fourth person pays, you first calculate the total fraction paid by the first three people: 1/3 + 1/4 + 1/6 = 4/12 + 3/12 + 2/12 = 9/12 = 3/4. This means that the first three people paid 3/4 of the bill. Therefore, the fourth person pays the remaining fraction: 1 - 3/4 = 1/4. So, the fourth person pays 1/4 of the bill. Choice A, 1/4, is incorrect because this is the total fraction paid by the first person. Choice B, 1/6, is incorrect as this is the fraction paid by the second person. Choice C, 1/3, is incorrect as this is the fraction paid by the third person.

3. Prizes are to be awarded to the best pupils in each class of an elementary school. The number of students in each grade is shown in the table, and the school principal wants the number of prizes awarded in each grade to be proportional to the number of students. If there are twenty prizes, how many should go to fifth-grade students? Grade 1 2 3 4 5 Students 35 38 38 33 36

• A. 5
• B. 4
• C. 7
• D. 3

Correct answer: C

Rationale: To determine how many prizes should be awarded to 5th-grade students, we need to set up the proportion of the number of 5th-grade students to the total number of students in the school. The total number of students is 35 + 38 + 38 + 33 + 36 = 180 students. To find the proportion of 5th-grade students, it would be 36/180 = 0.2. Since there are 20 prizes to be awarded, multiplying 0.2 by 20 gives us 4, which means 4 prizes should go to the 5th-grade students. Therefore, the correct answer is 4. Choice A (5) is incorrect as it does not align with the proportional distribution. Choice B (4) is the correct answer, as calculated. Choice C (7) is incorrect as it exceeds the total number of prizes available. Choice D (3) is incorrect as it does not match the proportional distribution based on the number of students.

4. Which is bigger, a mile or a kilometer? What's the conversion factor?

• A. Mile is bigger; 1 mile is 1.609 km
• B. Kilometer is bigger; 1 km is 1.609 miles
• C. Mile is bigger; 1 mile is 1.5 km
• D. Kilometer is bigger; 1 km is 2 miles

Correct answer: A

Rationale: A mile is bigger than a kilometer. The correct conversion factor is 1 mile = 1.609 km. This means that one mile is equivalent to approximately 1.609 kilometers. Choice B is incorrect because a mile is bigger than a kilometer, and the conversion is not 1 km = 1.609 miles. Choice C is incorrect as the conversion factor provided is inaccurate; 1 mile is not equal to 1.5 km. Choice D is incorrect as it states that a kilometer is bigger, which is not true according to the actual conversion factor.

5. How many whole boxes measuring 2 ft * 2 ft * 2 ft can be stored in a room measuring 9 ft * 9 ft * 9 ft, without altering the box size?

• A. 125
• B. 64
• C. 18
• D. 92

Correct answer: D

Rationale: The total volume of the room is 729 ft³ (9 ft * 9 ft * 9 ft). Each box has a volume of 8 ft³ (2 ft * 2 ft * 2 ft). Dividing the room's volume by the box volume, we get 729 ft³ / 8 ft³ ≈ 91.125. Since we can't have a fraction of a box, the maximum number of whole boxes that can fit is 92. Therefore, the correct answer is 92. Choice A (125) is incorrect as it does not result from the correct calculation. Choice B (64) and Choice C (18) are also incorrect and do not accurately represent the number of boxes that can fit in the room based on the given dimensions.

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