Nursing Elites

1. The immune response can be categorized into two main branches:

• A. Humoral and cellular
• B. Innate and adaptive
• C. Primary and secondary
• D. Active and passive

Correct answer: A

Rationale: - The immune response can be broadly categorized into two main branches: the humoral immune response and the cellular immune response. - The humoral immune response involves the production of antibodies by B cells and is primarily responsible for defending against extracellular pathogens such as bacteria and viruses in the bloodstream and tissues. - The cellular immune response involves the activation of T cells, which can directly kill infected cells or help coordinate the immune response. This branch is crucial for combating intracellular pathogens like viruses and some bacteria. - Options B, C, and D do not accurately represent the main branches of the immune response and are therefore incorrect.

2. What is the primary function of red blood cells in the cardiovascular system?

• A. To transport oxygen throughout the body.
• B. To fight infection and disease.
• C. To help regulate blood clotting.
• D. To remove waste products from the body.

Correct answer: A

Rationale: Red blood cells, also known as erythrocytes, play a crucial role in the cardiovascular system by primarily transporting oxygen from the lungs to the body's tissues and organs. This essential function is carried out through the interaction of hemoglobin, a protein within red blood cells, which binds to oxygen in the lungs and releases it in the body's tissues. Choices B, C, and D are incorrect. Red blood cells are not actively involved in fighting infections, regulating blood clotting, or eliminating waste products from the body.

3. Balance the chemical equation: C4H10 + O2 → CO2 + H2O. What is the coefficient for oxygen?

• A. 5
• B. 6
• C. 7
• D. 8

Correct answer: B

Rationale: To balance the chemical equation, we need to ensure that the number of each type of atom is the same on both sides of the equation. In this case, there are 10 oxygen atoms on the right side (5 in CO2 and 5 in H2O). To balance this, we need to add a coefficient of 6 in front of O2 on the left side, resulting in 6 O2 molecules. This change will give us a total of 12 oxygen atoms on both sides, making the equation balanced. Choice A (5) is incorrect because it does not account for all the oxygen atoms present in the products. Choices C (7) and D (8) are incorrect as they would result in an imbalance in the number of oxygen atoms on both sides of the equation.

4. What is the main function of the gallbladder?

• A. To store and concentrate bile
• B. To produce digestive enzymes
• C. To absorb nutrients
• D. To neutralize stomach acid

Correct answer: A

Rationale: The gallbladder is a small organ located beneath the liver that plays a crucial role in the digestive system. Its main function is to store and concentrate bile, a digestive fluid produced by the liver. Bile is released from the gallbladder into the small intestine to help with the digestion and absorption of fats. The gallbladder acts as a reservoir for bile, allowing it to be released in a controlled manner when needed to aid in the digestion of fatty foods. Option A is the correct answer as it accurately describes the main function of the gallbladder. Choices B, C, and D are incorrect because the gallbladder does not produce digestive enzymes, absorb nutrients, or neutralize stomach acid. These functions are carried out by other organs in the digestive system, such as the pancreas, small intestine, and stomach, respectively.

5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

• A. 18.3 g
• B. 19.7 g
• C. 21.0 g
• D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

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