Nursing Elites

1. What is the solution to the equation 4y - 6 = 14? Solve for y.

• A. 4
• B. 5
• C. 6
• D. 7

Correct answer: B

Rationale: To solve the equation 4y - 6 = 14 for y, isolate y by adding 6 to both sides: 4y = 14 + 6 => 4y = 20. Then, divide by 4 to solve for y: y = 20 ÷ 4 = 5. Therefore, the correct answer is 5. Choice A is incorrect as it does not represent the correct solution to the equation. Choice C is incorrect as it is not the solution obtained after correctly solving the equation. Choice D is incorrect as it is not the correct solution to the given equation.

2. Add 7/8 + 9/10 + 6/5. Express the result as a mixed number.

• A. 3 & 39/40
• B. 3 & 22/23
• C. 22/23
• D. 2 & 39/40

Correct answer: A

Rationale: To add fractions, find a common denominator, which in this case is 40. Convert each fraction to have the common denominator: 7/8 = 35/40, 9/10 = 36/40, and 6/5 = 48/40. Add these fractions to get 119/40. Simplify this improper fraction to a mixed number, which is 3 & 39/40. Choice B and C are incorrect as they do not represent the sum of the fractions. Choice D is incorrect; the whole number part should be 3, not 2.

3. Solve for x: 3x + 2 = 14

• A. x = 4
• B. x = 2
• C. x = 6
• D. x = 3

Correct answer: A

Rationale: To solve the equation 3x + 2 = 14, first, subtract 2 from both sides to isolate 3x: 3x = 12. Then, divide by 3 to solve for x: x = 4. Therefore, the correct answer is A, x = 4. Choice B, x = 2, is incorrect because it does not satisfy the equation. Choice C, x = 6, is incorrect as well since it does not satisfy the equation. Choice D, x = 3, is also incorrect as it does not satisfy the given equation.

4. What is the result of adding 5 2/9 and 1 2/9?

• A. 6 4/9
• B. 7 5/9
• C. 7
• D. 5 2/9

Correct answer: A

Rationale: To add mixed numbers with fractions, first add the whole numbers together: 5 + 1 = 6. Then add the fractions: 2/9 + 2/9 = 4/9. Combining the whole number and the fraction parts gives 6 4/9. Therefore, the correct answer is 6 4/9. Choice B (7 5/9) is incorrect as the fractions were not added correctly. Choice C (7) is incorrect as it does not account for the fractions. Choice D (5 2/9) is one of the original numbers and not the sum of both.

5. A solution is 60% alcohol. If 200ml of the solution is used, how much pure alcohol is present?

• A. 100ml
• B. 120ml
• C. 140ml
• D. 160ml

Correct answer: B

Rationale: If the solution is 60% alcohol, it means that 60% of the solution is alcohol. Therefore, in 200ml of the solution, the amount of alcohol present is: 200ml * 60% = 200ml * 0.60 = 120ml. So, when 200ml of the solution is used, there are 120ml of pure alcohol present. Choice A, 100ml, is incorrect because it does not account for the correct percentage of alcohol in the solution. Choice C, 140ml, and Choice D, 160ml, are incorrect as they overestimate the amount of pure alcohol present in the solution.

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