HESI A2
HESI A2 Vocabulary 2024
1. Choose the meaning of the word 'sanguinary' in the following sentence: 'Surgery is often a sanguinary procedure.'
- A. Hopeful or cheerful
- B. Involving bloodshed
- C. Difficult and protracted
- D. Tricky and sensitive
Correct answer: B
Rationale: The word 'sanguinary' is derived from the Latin word 'sanguinarius,' meaning bloodthirsty or bloodshed. In the context of the sentence, 'sanguinary' is used to indicate that surgery is a procedure that involves bloodshed. Therefore, the correct answer is B. Choice A ('Hopeful or cheerful') is incorrect because 'sanguinary' does not convey a positive or cheerful meaning. Choice C ('Difficult and protracted') is incorrect as 'sanguinary' specifically relates to blood or bloodshed, not difficulty or prolongation. Choice D ('Tricky and sensitive') is incorrect as 'sanguinary' does not imply trickiness or sensitivity but rather the presence of blood or bloodshed.
2. 7:5=91:x. Find x.
- A. x=65
- B. x=55
- C. x=75
- D. x=85
Correct answer: A
Rationale: To solve the proportion 7:5=91:x, cross multiply to get 7x = 5 * 91. Then, solve for x by dividing both sides by 7, which gives x = 65. Therefore, the correct answer is x=65. Choice B, x=55, is incorrect because it does not satisfy the proportion equation. Choices C and D, x=75 and x=85, are also incorrect as they do not match the calculated value of x when the proportion is solved.
3. What is the primary function of hemoglobin in red blood cells?
- A. To transport nutrients
- B. To fight infections
- C. To carry oxygen
- D. To produce energy
Correct answer: C
Rationale: The correct answer is C: 'To carry oxygen.' Hemoglobin in red blood cells binds to oxygen in the lungs and transports it to the tissues and organs throughout the body. This oxygen transport is crucial for cellular respiration and the overall functioning of the body. Choices A, B, and D are incorrect because hemoglobin's primary function is not to transport nutrients, fight infections, or produce energy in red blood cells.
4. Add and simplify: 4⅔ + 6½ =
- A. 11⅙
- B. 10⅓
- C. 9⅙
- D. 9
Correct answer: C
Rationale: To add 4⅔ and 6½, we first need to convert the fractions to have the same denominator. Converting 4⅔ to 6ths gives us 8/6, and 6½ to 6ths gives us 7/2. Adding them together gives 15/2, which simplifies to 7½ or 9⅙. Therefore, the correct answer is 9⅙. Choices A, B, and D are incorrect as they do not represent the correct sum of the fractions after conversion and simplification.
5. Cobalt-60 has a half-life of 5 years. If you start with 20 g of cobalt-60, how much is left after 10 years?
- A. 15 g
- B. 10 g
- C. 5 g
- D. 2.5 g
Correct answer: C
Rationale: Cobalt-60's half-life of 5 years means that after 5 years, half of the initial amount remains. Therefore, after 10 years, a quarter (half of a half) of the initial amount will remain. Starting with 20 g, after 10 years, 5 g of cobalt-60 will be left. Choice A (15 g) is incorrect because it assumes a linear decrease, not considering the exponential decay characteristic of radioactive substances. Choice B (10 g) is incorrect as it overlooks that after 10 years, more decay has occurred. Choice D (2.5 g) is incorrect as it represents only an eighth of the initial amount after 10 years, not a quarter.
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