Nursing Elites

1. What is the value of x in the ratio and proportion 0.1:10=x:400?

• A. 5
• B. 4
• C. 50
• D. 25

Correct answer: B

Rationale: To solve the proportion 0.1:10=x:400, first, simplify the left side to 1:100. Then, set up the proportion as 1:100=x:400. Cross multiply to get x = 4. Therefore, the correct answer is B. Choice A (5) is incorrect because it does not match the calculated value of x. Choice C (50) is incorrect as it is not the result of solving the proportion provided. Choice D (25) is incorrect as it does not align with the correct calculation of x.

2. A table shows the average blood pressure readings for different age groups. How do you determine the highest average systolic pressure?

• A. Find the largest number in the "systolic pressure" column.
• B. Compare the means (averages) of each age group.
• C. Add all systolic pressure values and divide by the total number of patients.
• D. Subtract the lowest systolic pressure from the highest.

Correct answer: A

Rationale: Rationale: - To determine the highest average systolic pressure, you need to identify the highest individual systolic pressure reading in the dataset. - Option A instructs you to find the largest number in the "systolic pressure" column, which directly addresses the task of identifying the highest systolic pressure reading. - Comparing means (Option B) would not necessarily give you the highest individual systolic pressure reading, as averages can be influenced by the distribution of values within each age group. - Adding all systolic pressure values and dividing by the total number of patients (Option C) would give you the overall average systolic pressure, not the highest individual reading. - Subtracting the lowest systolic pressure from the highest (Option D) would give you the range of systolic pressures, not specifically the highest individual reading. Therefore, the correct approach to determine the highest average systolic pressure

3. Gus is making a chili recipe that calls for three parts beans to five parts ground beef. If he is using 8 cups of ground beef for a big family dinner, how many cups of beans will Gus need?

• A. 3.6 cups
• B. 4 cups
• C. 4.6 cups
• D. 4.8 cups

Correct answer: B

Rationale: For every 3 parts of beans, Gus needs 5 parts of ground beef. This means the ratio of beans to beef is 3:5. If Gus is using 8 cups of ground beef, the total parts would be 3 parts beans to 5 parts beef, which is a total of 8 parts. To find out how many cups of beans Gus needs, we can set up a proportion: 3/5 = x/8. Cross multiplying gives us 5x = 24. Solving for x, we get x = 4. Therefore, Gus will need 4 cups of beans. Choice A, C, and D are incorrect as they do not align with the correct proportion calculation.

4. If a dice is rolled, what is the probability of getting an even number?

• A. 16%
• B. 33%
• C. 66%
• D. 50%

Correct answer: D

Rationale: When rolling a standard six-sided die, there are three even numbers (2, 4, 6) out of a total of six possible outcomes (1, 2, 3, 4, 5, 6). The probability of rolling an even number can be calculated as the number of favorable outcomes (3) divided by the total number of outcomes (6), which equals 3/6 = 50%. Therefore, the correct answer is D. Choice A (16%) is incorrect because it does not represent the probability of rolling an even number. Choice B (33%) is incorrect as it does not reflect the correct probability. Choice C (66%) is incorrect as well since it overestimates the probability.

5. What is the probability of rolling a 4 on a six-sided die?

• A. 1/2
• B. 1/6
• C. 1/3
• D. 1/2

Correct answer: B

Rationale: The correct answer is B: 1/6. When rolling a six-sided die, there is only one outcome that results in a '4' out of a total of six possible outcomes (1, 2, 3, 4, 5, 6). Therefore, the probability of rolling a 4 is 1/6. Choice A (1/2) is incorrect as it represents the probability of rolling an even number on a six-sided die, not specifically a '4.' Choice C (1/3) and Choice D (1/2) do not accurately reflect the probability of rolling a '4' on a six-sided die.

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