Nursing Elites

1. What are polymers?

• A. Large molecules formed by repeating units called monomers
• B. Simple organic molecules with low boiling points
• C. Highly reactive compounds used in industrial processes
• D. Insoluble solids with no definite structure

Correct answer: A

Rationale: Polymers are large molecules formed by repeating units called monomers. These monomers link together to form long chains or networks, giving polymers their unique properties such as flexibility, strength, and durability. Choice B is incorrect because polymers are not simple organic molecules with low boiling points, but rather complex structures formed by polymerization. Choice C is incorrect as polymers are not necessarily highly reactive compounds, and they are not exclusively used in industrial processes. Choice D is incorrect because polymers can have varying solubilities and structures depending on their composition and properties.

2. Which of the following types of immunity is provided by the secretion of antibodies by B-cells?

• A. Cell-mediated
• B. Humoral
• C. Innate immunity
• D. Phagocytic

Correct answer: B

Rationale: The correct answer is B: Humoral. Humoral immunity involves B-cells secreting antibodies to fight pathogens. In this type of immunity, antibodies circulate in the blood and other body fluids to neutralize pathogens and prevent infections. Cell-mediated immunity, on the other hand, involves the activation of T-cells to directly attack infected or abnormal cells, not the secretion of antibodies. Innate immunity refers to the nonspecific defense mechanisms the body has in place from birth, such as physical barriers and inflammatory responses. Phagocytic immunity is not a recognized type of immunity; phagocytosis is a mechanism used by cells like macrophages to engulf and digest pathogens, but it is not a specific form of immunity like humoral or cell-mediated immunity.

3. What characteristic unites all organisms in the kingdom Animalia?

• A. Multicellularity and heterotrophy
• B. Unicellular nature
• C. Photosynthesis
• D. Cell walls made of chitin

Correct answer: A

Rationale: A) Multicellularity and heterotrophy: This is the correct answer because all organisms in the kingdom Animalia are multicellular (composed of multiple cells) and exhibit heterotrophy (obtain nutrients by consuming other organisms). B) Unicellular nature: This is incorrect because organisms in the kingdom Animalia are multicellular, not unicellular. C) Photosynthesis: This is incorrect because organisms in the kingdom Animalia do not perform photosynthesis; they are heterotrophs that obtain nutrients by consuming other organisms. D) Cell walls made of chitin: This is incorrect because organisms in the kingdom Animalia do not have cell walls made of chitin. Chitin is a structural polysaccharide found in the cell walls of fungi, not animals.

4. What happens when an atom loses an electron?

• A. It forms a molecule.
• B. It gains a positive charge and becomes an ion.
• C. It alters its elemental identity.
• D. No change occurs; it remains neutral.

Correct answer: B

Rationale: When an atom loses an electron, it gains a positive charge and becomes an ion. This occurs because the number of protons in the atom exceeds the number of electrons, leading to a positive charge. Therefore, the atom undergoes a transformation into an ion by losing an electron. Choice A is incorrect because losing an electron does not result in the formation of a molecule, as molecules are made up of bonded atoms. Choice C is incorrect because losing an electron does not change the fundamental identity of the atom; it only changes its charge. Choice D is incorrect because losing an electron causes the atom to become positively charged, altering its neutrality.

5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.

• A. 18.3 g
• B. 19.7 g
• C. 21.0 g
• D. 24.2 g

Correct answer: B

Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.

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