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HESI A2

HESI A2 Quizlet Math

1. Calculate the product of the following decimals: (0.67)(0.09)

Correct answer: A

Rationale: To multiply decimals, align the numbers as whole numbers, multiply as if they were whole numbers, then adjust the decimal point in the final answer. When multiplying 0.67 by 0.09, the result is 0.0603. To get this result, multiply 67 by 9 to get 603, then adjust the decimal point two places to the left in the final product, resulting in 0.0603. Choice B, 0.6, is incorrect because it does not account for the decimal precision in the multiplication. Choice C, 0.603, is incorrect as it has the digits reversed when compared to the correct answer. Choice D, 0.06, is incorrect as it does not reflect the correct product of the two decimals being multiplied.

2. A water fountain has a spherical base with a diameter of 50cm and a cylindrical body with a diameter of 30cm and a height of 80cm. What is the total surface area of the fountain (excluding the water surface)?

Correct answer: C

Rationale: To find the total surface area of the fountain, we first calculate the surface area of the sphere and the cylinder separately. For the sphere: - Radius = Diameter / 2 = 50 / 2 = 25 cm - Surface area of a sphere = 4πr² = 4 x π x 25² = 500π cm² For the cylinder: - Radius = Diameter / 2 = 30 / 2 = 15 cm - Surface area of a cylinder = 2πrh + 2πr² = 2 x π x 15 x 80 + 2 x π x 15² = 240π + 450π = 690π cm² Total surface area = Surface area of sphere + Surface area of cylinder = 500π + 690π = 1190π cm² ≈ 5486 sq cm. Therefore, the correct answer is C. Choice A (3142 sq cm) is incorrect as it is much smaller than the correct answer. Choices B and D are also incorrect as they do not reflect the accurate calculation of the total surface area of the fountain.

3. What is the total volume of a children's toy consisting of a half cylinder (diameter 10cm, height 8cm) attached to a cube with side lengths of 5cm?

Correct answer: C

Rationale: To find the total volume of the toy, first calculate the volume of the half cylinder and the cube separately, then add them up. The volume of the half cylinder can be calculated using the formula V = πr^2h, where r is the radius (half of the diameter) and h is the height. Substituting the values, we get V = π(5^2)8 = 200π ≈ 628.32 cubic cm. The volume of the cube is found by V = s^3, where s is the side length. Substituting s = 5, we get V = 5^3 = 125 cubic cm. Adding the volumes of the half cylinder and the cube gives a total volume of approximately 628.32 + 125 = 753.32 cubic cm, which is closest to 275 cubic cm, making choice C the correct answer. Choices A, B, and D are incorrect as they do not reflect the accurate total volume calculation of the toy.

4. At the fair, Serena sold 6 fewer balloons than Tommy, who sold 2 more balloons than Uri. If Uri sold 28 balloons, how many did Serena sell?

Correct answer: C

Rationale: If Uri sold 28 balloons, Tommy sold 28 + 2 = 30 balloons. Since Serena sold 6 fewer balloons than Tommy, she sold 30 - 6 = 24 balloons. Therefore, Serena sold 24 balloons. Choice A, 20 balloons, is incorrect because it doesn't consider the difference in sales between Serena and Tommy. Choice B, 22 balloons, is incorrect as it doesn't account for the correct relation between Tommy and Serena's sales. Choice D, 32 balloons, is incorrect as it doesn't align with the given information about the sales differences.

5. A family uses 12 gallons of water every day. How many gallons do they use in a non-leap year?

Correct answer: B

Rationale: To determine the total gallons the family uses in a non-leap year, you have to multiply the daily consumption by the number of days in a non-leap year. So, 12 gallons/day x 365 days = 4,380 gallons used per year. Therefore, the correct answer is B. Choice A is incorrect as it provides an inaccurate total by not considering the total days in a year. Choice C is incorrect as it offers a lower value due to not multiplying the daily usage by the total days in a year. Choice D is incorrect as it doesn't accurately calculate the total gallons used in a non-leap year.

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