Nursing Elites

1. When recording the childhood illnesses of a patient who denies having had any, which note by the nurse would be most accurate?

• A. Patient denies usual childhood illnesses.
• B. Patient states he was a 'very healthy' child.
• C. Patient states sister had measles, but he didn't.
• D. Patient denies measles, mumps, rubella, chickenpox, pertussis, and strep throat.

Correct answer: D

Rationale: Choice D is the most accurate note by the nurse as it lists specific childhood illnesses commonly experienced by children. By documenting that the patient denies having had these specific illnesses, the healthcare provider establishes a clear medical history record regarding these common childhood illnesses. This detailed documentation is essential for providing comprehensive care and evaluating potential risks or complications associated with these illnesses in the future. Choices A, B, and C are not as accurate as they do not provide a comprehensive list of common childhood illnesses that are routinely evaluated by healthcare providers. Choice A is too vague, Choice B focuses on the patient's perception of their health rather than specific illnesses, and Choice C only mentions measles, lacking the breadth of information provided in Choice D.

2. A car, starting from rest, accelerates at 10 m/s² for 5 seconds. What is the velocity of the car after 5 seconds?

• A. 2 m/s
• B. 5 m/s
• C. 50 m/s
• D. The answer cannot be determined from the information given.

Correct answer: C

Rationale: The velocity of an object can be calculated using the formula: final velocity = initial velocity + (acceleration × time). In this case, the car starts from rest, so the initial velocity is 0 m/s. Given that the acceleration is 10 m/s² and the time is 5 seconds, we can plug these values into the formula to find the final velocity: final velocity = 0 m/s + (10 m/s² × 5 s) = 0 m/s + 50 m/s = 50 m/s. Therefore, the velocity of the car after 5 seconds is 50 m/s. Choice A (2 m/s) and Choice B (5 m/s) are incorrect because they do not consider the acceleration the car undergoes over the 5 seconds, resulting in a final velocity greater than both. Choice D (The answer cannot be determined from the information given) is incorrect as the final velocity can be determined using the provided data and the kinematic equation.

3. If a runner runs 5 miles in 45 minutes, what is their average speed in miles per hour?

• A. 6.67 mph
• B. 5 mph
• C. 7 mph
• D. 10 mph

Correct answer: A

Rationale: To find the average speed, first, convert 45 minutes to hours (45/60 = 0.75 hours). Then, divide the distance by the time: 5 miles ÷ 0.75 hours = 6.67 mph. Choice A is correct because it accurately calculates the average speed based on the distance covered and time taken. Choice B is incorrect as it does not consider the time taken to cover the distance. Choice C is incorrect as it is higher than the calculated speed. Choice D is incorrect as it is higher and does not match the calculated average speed.

4. Ventral refers to which part of the body?

• A. Top
• B. Bottom
• C. Front
• D. Back

Correct answer: C

Rationale: Ventral refers to the front part of the body or an organ. It is the opposite of dorsal, which refers to the back part. So, when describing the direction or location of an anatomical structure, ventral would mean towards the front. Therefore, the correct answer is 'Front.' Choices A, B, and D are incorrect because 'Top' refers to superior, 'Bottom' refers to inferior, and 'Back' refers to dorsal, not ventral.

5. A hospital day staff consists of 25 registered nurses, 75 unlicensed assistants, 5 phlebotomists, 6 receptionists, and 45 physicians. On one particular day, the staff was at only 68% strength. How many people were working that day? (Round to the nearest whole number).

• A. 102
• B. 106
• C. 98
• D. 110

Correct answer: B

Rationale: To find the total staff working that day, add up all the staff members: 25 registered nurses + 75 unlicensed assistants + 5 phlebotomists + 6 receptionists + 45 physicians = 156 staff members. Since the staff was at 68% strength, multiply 156 by 0.68 to get 106. Therefore, approximately 106 people were working that day. Choice A, 102, is incorrect because it underestimates the total staff. Choice C, 98, is incorrect because it is too low. Choice D, 110, is incorrect because it overestimates the total staff.

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