fertilization the fusion of sperm and egg typically occurs in which part of the female reproductive system
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ATI TEAS 7

TEAS Test 7 science

1. Where does fertilization, the fusion of sperm and egg, typically occur in the female reproductive system?

Correct answer: B

Rationale: Fertilization typically occurs in the fallopian tube. After ovulation, the egg is released from the ovary and travels through the fallopian tube, where it may encounter sperm for fertilization. The fallopian tube is the site where the sperm fertilizes the egg before the fertilized egg continues its journey towards the uterus for implantation. The ovary is where the egg is produced but not where fertilization occurs. The uterus is where the fertilized egg implants and develops into a fetus, not where fertilization takes place. The vagina is part of the birth canal and not the typical site for fertilization in the female reproductive system.

2. Which property of a substance describes how much matter is packed into a given space?

Correct answer: D

Rationale: Density is the property of a substance that describes how much matter is packed into a given space. It is calculated by dividing the mass of the substance by its volume. Mass refers to the amount of matter in an object, volume is the amount of space an object occupies, and weight is the force of gravity acting on an object's mass. Density specifically relates to how tightly packed the particles of a substance are. In this context, density is the most appropriate answer as it directly addresses how matter is packed into a given space. Mass and weight are related to the quantity of matter and the force of gravity, respectively, but do not directly describe the compactness of matter in a given space. Volume, on the other hand, refers to the space occupied by an object, not the amount of matter packed into that space.

3. If you compare a 1 M solution of NaCl to a 1 M solution of glucose (C6H12O6) in water, which solution would have the higher boiling point?

Correct answer: A

Rationale: 1. Boiling point elevation: When a solute is added to a solvent, it raises the boiling point of the solution compared to the pure solvent. This phenomenon is known as boiling point elevation. 2. Van't Hoff factor: The extent of boiling point elevation depends on the number of particles the solute dissociates into in the solution. NaCl dissociates into two ions (Na+ and Cl-) in water, while glucose does not dissociate into ions. Therefore, NaCl has a higher Van't Hoff factor than glucose. 3. Colligative properties: Boiling point elevation is a colligative property, meaning it depends on the concentration of the solute particles, not the identity of the solute. Since both NaCl and glucose are 1 M solutions, the NaCl solution will have a higher boiling point due to its higher Van't Hoff factor. 4. Conclusion: The NaCl solution

4. Based on the following evidence, what is the most likely reason that spoiled food left out in the open often contains fly larvae?

Correct answer: B

Rationale: The correct answer is B. Flies laying eggs in the food when it is left exposed to the air is a common occurrence and a logical explanation for the presence of fly larvae in spoiled food. Choice A is incorrect as food cannot evolve into fly larvae; fly larvae come from eggs laid by flies. Choice C is incorrect as fly larvae do not spontaneously generate from spoiled food but rather develop from eggs laid by flies. Choice D is incorrect as the presence of fly larvae in spoiled food is a real phenomenon, not merely imagined by people.

5. Balance the following redox reaction in acidic solution: I⁻ (aq) + Cr₂O₇²⁻ (aq) -> I₂ (aq) + Cr³⁺ (aq). Identify the oxidizing agent and reducing agent.

Correct answer: B

Rationale: In the given redox reaction, I⁻ is gaining electrons to form I₂, which means I⁻ is being reduced (undergoing reduction). On the other hand, Cr₂O₇²⁻ is losing electrons to form Cr³⁺, indicating that Cr₂O₇²⁻ is being oxidized (undergoing oxidation). Therefore, I⁻ is the reducing agent and Cr₂O₇²⁻ is the oxidizing agent. Choice A is incorrect because I⁻ is being reduced, not oxidized. Choice C is incorrect as both species cannot be oxidized in the same reaction. Choice D is incorrect as both species cannot be reduced in the same reaction.

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