HESI A2
HESI A2 Physics Quizlet
1. Entropy (S) is a thermodynamic property related to the system's disorder. According to the second law of thermodynamics, in a spontaneous process:
- A. The total entropy of the system and surroundings increases.
- B. The total entropy of the system and surroundings decreases.
- C. The total entropy of the system remains constant.
- D. The total entropy of the surroundings increases, while the system's entropy decreases.
Correct answer: A
Rationale: The second law of thermodynamics asserts that the entropy of an isolated system (or the combined system and surroundings) will always increase in a spontaneous process, reflecting an increase in disorder. Therefore, the correct answer is that the total entropy of the system and surroundings increases. Choice B is incorrect because entropy always tends to increase in a spontaneous process, as dictated by the second law of thermodynamics. Choice C is incorrect as entropy typically increases in natural processes. Choice D is incorrect because the second law of thermodynamics states that the total entropy of the system and surroundings always increases in a spontaneous process.
2. What is 25% of 200?
- A. 50
- B. 60
- C. 25
- D. 30
Correct answer: A
Rationale: To find 25% of a number, you multiply the number by 0.25. So, to calculate 25% of 200, you do 0.25 × 200 = 50. Therefore, the correct answer is A. Choice B (60) is incorrect as it is the result of calculating 30% of 200. Choice C (25) is incorrect as it represents 12.5% of 200. Choice D (30) is incorrect as it is the result of calculating 15% of 200.
3. A salt solution has a molarity of 5 M. How many moles of this salt are present in 0 L of this solution?
- A. 0
- B. 1.5
- C. 2
- D. 3
Correct answer: A
Rationale: Molarity is defined as the number of moles of solute per liter of solution. A molarity of 5 M indicates there are 5 moles of salt in 1 liter of the solution. Since the volume of the solution is 0 liters, multiplying the molarity by 0 liters results in 0 moles of salt (5 moles/L x 0 L = 0 moles). Therefore, the correct answer is 0. Option B, 1.5, is incorrect because it doesn't consider the volume being 0 liters. Options C and D, 2 and 3 respectively, are also incorrect as they do not account for the zero volume of the solution. Hence, there are no moles of salt present in 0 liters of the solution.
4. Choose the meaning of the word 'sanctioned' in the following sentence: 'The professor sanctioned our field trip to the chemistry lab.'
- A. Organized
- B. Deterred
- C. Neglected
- D. Authorized
Correct answer: D
Rationale: In this context, the word 'sanctioned' means to authorize or approve. The sentence indicates that the professor gave permission for the field trip to the chemistry lab, which aligns with the meaning of 'authorized.' Choices A, B, and C are incorrect. 'Organized' does not fit the context as the sentence is about granting approval, not arranging. 'Deterred' means to discourage, which is the opposite of what the professor did. 'Neglected' means failed to care for or pay attention to, which is unrelated to the professor approving the field trip.
5. What role does water vapor play in the Water Cycle, as described in the passage?
- A. Water vapor is unnecessary in the water cycle.
- B. Water vapor plays a key role in precipitation.
- C. Water vapor is harmful to the environment.
- D. Water vapor cools the Earth's surface.
Correct answer: B
Rationale: The correct answer is B: 'Water vapor plays a key role in precipitation.' The passage clearly outlines the importance of water vapor in the water cycle. It explains that water vapor returns to the air from surface water and plants, and condenses back into droplets of liquid, forming clouds. These clouds eventually lead to precipitation like rain, snow, sleet, or hail. Choice A is incorrect as water vapor is crucial in the water cycle. Choice C is also incorrect as there is no mention of water vapor being harmful in the passage. Choice D is incorrect as the passage does not state that water vapor cools the Earth's surface; instead, it highlights its role in the formation of precipitation.
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