Nursing Elites

1. What is the result of adding 1/4 + 3/8?

• A. 5/8
• B. 7/12
• C. 2/3
• D. 1/2

Correct answer: A

Rationale: To add fractions with different denominators, find a common denominator. In this case, the common denominator of 4 and 8 is 8. Convert 1/4 to 2/8, then add it to 3/8. The sum is 5/8. Choice B (7/12) is incorrect as it is the result of adding 1/3 + 1/4. Choice C (2/3) is incorrect as it is the result of adding 3/8 + 1/4. Choice D (1/2) is incorrect as it is the result of adding 1/4 + 1/4.

2. Subtract 12 - 7 & 4\5.

• A. 4 & 4\5
• B. 5 & 4\5
• C. 4 & 1\5
• D. 5 & 1\5

Correct answer: C

Rationale: 12 - 7 & 4\5 equals 4 & 1\5.

3. How many ounces are in 8 1/4 pints?

• A. 128 oz
• B. 132 oz
• C. 136 oz
• D. 140 oz

Correct answer: B

Rationale: To convert pints to ounces, multiply by 16 because 1 pint equals 16 ounces. Therefore, 8 1/4 pints is equal to 8.25 x 16 = 132 ounces. Choices A, C, and D are incorrect as they do not reflect the correct conversion from pints to ounces.

4. You have orders to administer 20 mg of a certain medication to a patient. The medication is stored at a concentration of 4 mg per 5-mL dose. How many milliliters will need to be administered?

• A. 30 mL
• B. 25 mL
• C. 20 mL
• D. 15 mL

Correct answer: B

Rationale: To administer 20 mg of the medication, you would need 25 mL. This calculation is derived from the concentration of 4 mg per 5 mL. By setting up a proportion, you can determine that for 20 mg, 25 mL must be administered as follows: (20 mg / 4 mg) = (x mL / 5 mL). Solving for x results in x = 25 mL. Choice A is incorrect because it miscalculates the proportion. Choices C and D are incorrect as they do not account for the correct concentration of the medication.

5. A decorative box has a rectangular base (20cm by 15cm) and a hemispherical top with the same diameter as the base. What is the total surface area of the box (excluding the base)?

• A. 825 sq cm
• B. 1075 sq cm
• C. 1325 sq cm
• D. 1575 sq cm

Correct answer: C

Rationale: To find the total surface area of the box excluding the base, calculate the lateral surface area of the rectangular base and the surface area of the hemisphere. The lateral surface area of the rectangular base is 2(20cm x 15cm) = 600 sq cm. The surface area of the hemisphere is 2πr^2, where r is half the diameter of the base, so r = 10cm. Thus, the surface area of the hemisphere is 2π(10cm)^2 = 200π sq cm ≈ 628.32 sq cm. Add the lateral surface area of the base and the surface area of the hemisphere: 600 sq cm + 628.32 sq cm ≈ 1228.32 sq cm. Therefore, the total surface area of the box is approximately 1228.32 sq cm, which is closest to 1325 sq cm (Choice C). Choices A, B, and D are incorrect as they do not represent the accurate calculation of the total surface area of the box.

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