a roast was cooked at 325f in the oven for 4 hours the internal temperature rose from 32f to 145f what was the average rise in temperature per hour
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HESI A2

HESI A2 Practice Test Math

1. A roast was cooked at 325°F in the oven for 4 hours. The internal temperature rose from 32°F to 145°F. What was the average rise in temperature per hour?

Correct answer: C

Rationale: The temperature increased from 32°F to 145°F, resulting in a total increase of 145°F - 32°F = 113°F. Dividing this total increase by the 4 hours of cooking time gives an average rise of 113°F ÷ 4 = 28.25°F per hour, which can be rounded to 28°F per hour. Therefore, the correct answer is 28. Choice A (20) is incorrect because it does not reflect the actual average rise in temperature per hour. Choice B (32) is incorrect as it does not consider the total temperature increase and divide it by the total hours. Choice D (37°F/hr) is incorrect as it does not match the calculated average rise in temperature per hour.

2. A man can type 45 words per minute. How many words can he type in 20 minutes?

Correct answer: C

Rationale: To calculate the total number of words typed in 20 minutes, multiply the typing speed per minute (45 words) by the duration in minutes (20 minutes): 45 words/min × 20 min = 900 words. Therefore, the correct answer is 900 words. Choices A, B, and D are incorrect because they do not reflect the accurate calculation based on the given information.

3. The least common multiple (LCM) of two numbers is the smallest number that is a multiple of both. Which of the following represents the LCM of 14 and 21?

Correct answer: C

Rationale: Rationale: To find the least common multiple (LCM) of 14 and 21, we need to determine the smallest number that is a multiple of both 14 and 21. First, list the multiples of 14: 14, 28, 42, 56, 70, 84, ... Next, list the multiples of 21: 21, 42, 63, 84, ... The smallest number that appears in both lists is 42. Therefore, the LCM of 14 and 21 is 42.

4. A farmer wants to plant trees at the outside boundaries of his rectangular field with dimensions 650 meters × 780 meters. Each tree requires 5 meters of free space all around it from the stem. How much free area will be left?

Correct answer: A

Rationale: To calculate the area taken by the trees, we need to account for the space each tree requires. Each tree needs 5 meters of free space all around it, totaling 10 meters added to each dimension. Therefore, the new dimensions of the field are (650-10) meters by (780-10) meters. Calculating the area of the new field: (640m × 770m = 492,800m²). To find the free area remaining, subtract the new field's area from the original field's area: 507,000m² - 492,800m² = 14,200m². Therefore, the free area left after planting the trees is 14,200m². Choice A is the correct answer as it represents the free area left after planting the trees.

5. Calculate the product of the following decimals: (0.67)(0.09)

Correct answer: A

Rationale: To multiply decimals, align the numbers as whole numbers, multiply as if they were whole numbers, then adjust the decimal point in the final answer. When multiplying 0.67 by 0.09, the result is 0.0603. To get this result, multiply 67 by 9 to get 603, then adjust the decimal point two places to the left in the final product, resulting in 0.0603. Choice B, 0.6, is incorrect because it does not account for the decimal precision in the multiplication. Choice C, 0.603, is incorrect as it has the digits reversed when compared to the correct answer. Choice D, 0.06, is incorrect as it does not reflect the correct product of the two decimals being multiplied.

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