Nursing Elites

1. A patient's height is 1.65 meters and their weight is 75kg. Calculate their BMI and interpret the result.

• A. 23.1 (Normal)
• B. 25.3 (Overweight)
• C. 27.7 (Overweight)
• D. 32.8 (Obese)

Correct answer: C

Rationale: To calculate BMI, divide weight (75kg) by height squared (1.65m^2) to get BMI (27.7). A BMI of 27.7 falls within the 'overweight' category (25-29.9 BMI). Choice A is incorrect as a BMI of 23.1 would be in the 'normal' range (18.5-24.9 BMI). Choice B is incorrect as 25.3 falls within the 'overweight' category. Choice D is incorrect as 32.8 is in the 'obese' category (>30 BMI). Therefore, the correct answer is C.

2. What is the total perimeter of a playground fence that has a rectangular section (5m by 3m) attached to a semicircular section with a radius of 2m?

• A. 13m
• B. 16m
• C. 19m
• D. 22m

Correct answer: D

Rationale: To find the total perimeter, we first calculate the perimeter of the semicircle, which is half of a full circle, so the formula is π * radius. For the semicircle with a radius of 2m, the perimeter is approximately 3.14 * 2m = 6.28m. Next, we calculate the perimeter of the rectangular section by adding twice the length and twice the width (2 * length + 2 * width). For the rectangle with dimensions 5m by 3m, the perimeter is 2 * 5m + 2 * 3m = 10m + 6m = 16m. Finally, we sum the perimeters of the semicircle and the rectangle to get the total perimeter: 6.28m + 16m = 22.28m. Rounding to the nearest meter, the total perimeter is approximately 22m. Therefore, the correct answer is 22m. Choices A, B, and C are incorrect as they do not accurately calculate the total perimeter of the playground fence.

3. If 7 is to 9 as x is to 63, find the value of x.

• A. x = 49
• B. x = 39
• C. x = 50
• D. x = 59

Correct answer: A

Rationale: To find the value of x, set up the proportion 7/9 = x/63. Cross multiply to get 7*63 = 9*x. This simplifies to 441 = 9x. Divide both sides by 9 to solve for x, giving x = 49. Therefore, the correct answer is A. Choice B (x = 39), Choice C (x = 50), and Choice D (x = 59) are incorrect as they do not match the correct calculation based on the proportion set up.

4. A decorative box has a rectangular base (20cm by 15cm) and a hemispherical top with the same diameter as the base. What is the total surface area of the box (excluding the base)?

• A. 825 sq cm
• B. 1075 sq cm
• C. 1325 sq cm
• D. 1575 sq cm

Correct answer: C

Rationale: To find the total surface area of the box excluding the base, calculate the lateral surface area of the rectangular base and the surface area of the hemisphere. The lateral surface area of the rectangular base is 2(20cm x 15cm) = 600 sq cm. The surface area of the hemisphere is 2πr^2, where r is half the diameter of the base, so r = 10cm. Thus, the surface area of the hemisphere is 2π(10cm)^2 = 200π sq cm ≈ 628.32 sq cm. Add the lateral surface area of the base and the surface area of the hemisphere: 600 sq cm + 628.32 sq cm ≈ 1228.32 sq cm. Therefore, the total surface area of the box is approximately 1228.32 sq cm, which is closest to 1325 sq cm (Choice C). Choices A, B, and D are incorrect as they do not represent the accurate calculation of the total surface area of the box.

5. Temperature Conversion & Interpretation: A patient's body temperature is 102°F. Convert this to °C and assess if it indicates a fever.

• A. 37°C (Normal)
• B. 39°C (Low-grade fever)
• C. 39°C (Fever)
• D. 42°C (Hyperthermia)

Correct answer: C

Rationale: Rationale: 1. To convert Fahrenheit to Celsius, you can use the formula: °C = (°F - 32) x 5/9. 2. Given that the patient's body temperature is 102°F, we can calculate the equivalent temperature in Celsius: °C = (102 - 32) x 5/9 °C = 70 x 5/9 °C = 350/9 °C ≈ 38.9°C, which can be rounded to 39°C. 3. A body temperature of 39°C is considered to indicate a fever. Normal body temperature typically ranges from 36.1°C to 37.2°C, so a temperature of 39°C is higher than the normal range and suggests a fever. 4. Options A and B are incorrect as they do not reflect the conversion of 102°F to °C

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