Nursing Elites

1. A nurse working at a medical clinic earns $17.81 per hour. The nurse works three 8-hour shifts and one 12-hour shift every week and is paid weekly. Weekly deductions include federal tax $102.80, state tax $24.58, federal insurance $18.13, and family health insurance $52.15. What is the nurse's take-home pay each week?

• A. $443.50
• B. $450.00
• C. $500.00
• D. $430.00

Correct answer: A

Rationale: To calculate the nurse's take-home pay, first determine the weekly gross income. The nurse works 3 shifts x 8 hours = 24 hours at $17.81 per hour plus 1 shift x 12 hours = 12 hours at $17.81 per hour, totaling 36 hours. Therefore, the gross income is 36 hours x $17.81 = $641.16. Next, subtract the weekly deductions: federal tax $102.80 + state tax $24.58 + federal insurance $18.13 + family health insurance $52.15 = $197.66. Deducting $197.66 from the gross income gives $641.16 - $197.66 = $443.50 as the nurse's take-home pay each week. Therefore, the correct answer is $443.50. Choice B ($450.00) is incorrect because it does not consider the specific deductions provided. Choices C ($500.00) and D ($430.00) are also incorrect as they do not reflect the accurate calculation based on the given information.

2. What number is 80 125% of?

• A. 48
• B. 64
• C. 68
• D. 78

Correct answer: B

Rationale: To find the number that 80 is 125% of, we can set up the equation: x = 80 / 1.25. Solving this equation gives x = 64. Therefore, 80 is 125% of 64. Choice A (48) is incorrect because it is not the correct value that 80 is 125% of. Choice C (68) is incorrect as it is not the value that satisfies the given percentage relationship. Choice D (78) is incorrect as it does not match the calculation result.

3. A rancher has a herd of different-colored horses in his corral. Ten of the horses are black, six are brown, eight are two-color horses, and three are all white. What percentage of the horses are brown? (Round to the nearest whole number if necessary).

• A. 15%
• B. 20%
• C. 25%
• D. 30%

Correct answer: B

Rationale: To find the percentage of brown horses, first calculate the total number of horses: 10 black + 6 brown + 8 two-color + 3 all white = 27 horses. Then, calculate the percentage of brown horses: (6 ÷ 27) × 100 = 22.22%, which rounds to 20%. Choice B, 20%, is the correct answer. Choice A, 15%, is incorrect as it does not reflect the accurate percentage of brown horses. Choice C, 25%, is incorrect as it overestimates the percentage of brown horses. Choice D, 30%, is incorrect as it also overestimates the percentage of brown horses.

4. How many grams of carbohydrates are in a product if it contains 4 servings, and each serving has 8 grams of carbohydrates?

• A. 32 grams
• B. 28 grams
• C. 24 grams
• D. 20 grams

Correct answer: A

Rationale: To calculate the total grams of carbohydrates in the product, you multiply the number of servings by the grams of carbohydrates per serving. Given that each serving has 8 grams of carbohydrates and there are 4 servings, the total would be 4 servings * 8 grams = 32 grams. Therefore, the correct answer is A: 32 grams. Choices B, C, and D are incorrect as they do not correctly calculate the total grams of carbohydrates based on the information provided.

5. Temperature Conversion & Interpretation: A patient's body temperature is 102°F. Convert this to °C and assess if it indicates a fever.

• A. 37°C (Normal)
• B. 39°C (Low-grade fever)
• C. 39°C (Fever)
• D. 42°C (Hyperthermia)

Correct answer: C

Rationale: Rationale: 1. To convert Fahrenheit to Celsius, you can use the formula: °C = (°F - 32) x 5/9. 2. Given that the patient's body temperature is 102°F, we can calculate the equivalent temperature in Celsius: °C = (102 - 32) x 5/9 °C = 70 x 5/9 °C = 350/9 °C ≈ 38.9°C, which can be rounded to 39°C. 3. A body temperature of 39°C is considered to indicate a fever. Normal body temperature typically ranges from 36.1°C to 37.2°C, so a temperature of 39°C is higher than the normal range and suggests a fever. 4. Options A and B are incorrect as they do not reflect the conversion of 102°F to °C

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