ATI TEAS 7
Science TEAS Practice Test
1. A dietitian wants to convince a patient to lose weight. Which statement below best communicates a scientific argument that justifies the need for weight loss?
- A. Losing weight can lower blood pressure, increase energy levels, and promote overall health.
- B. Society tends to treat overweight people unfairly.
- C. Members of the opposite sex are more interested in people who maintain a healthy weight.
- D. Losing weight is easy to do.
Correct answer: A
Rationale: Choice A is the correct answer as it provides a scientific argument supported by evidence. Losing weight has been shown to lower blood pressure, increase energy levels, and promote overall health. These are concrete health benefits that can be objectively measured and monitored. Choices B and C do not offer scientific justifications for weight loss but rather focus on societal perceptions and personal relationships. Choice D is incorrect as losing weight is not always easy and may require significant effort and lifestyle changes.
2. What is the study of fungi known as?
- A. Virology
- B. Mycology
- C. Bacteriology
- D. Parasitology
Correct answer: B
Rationale: Mycology is the correct answer. Mycology is the branch of biology that specifically deals with the study of fungi. Fungi constitute a separate kingdom of organisms that include various forms such as yeasts, molds, and mushrooms. Virology (A) is the study of viruses, while Bacteriology (C) focuses on bacteria. Parasitology (D) is the study of parasites, which may include protozoa, helminths, and some fungi, but it is not solely dedicated to fungi.
3. Why do Neon (Ne) and Helium (He) belong to Group 18 (Noble Gases)?
- A. Electromagnetism
- B. Gravity
- C. Strong nuclear force
- D. Weak nuclear force
Correct answer: A
Rationale: Neon (Ne) and Helium (He) belong to Group 18 (Noble Gases) because they have complete and stable outer electron shells. The stability of these outer electron shells is due to the balance of attractive forces between the positively charged protons in the nucleus and the negatively charged electrons in the outer shell. This balance is maintained by the electromagnetic force, which is responsible for holding atoms together and determining their chemical properties. Gravity (Choice B) is a force of attraction between objects with mass and is not responsible for the stability of electron shells. The strong nuclear force (Choice C) and weak nuclear force (Choice D) are forces that act within the nucleus of an atom and are not directly related to the stability of outer electron shells in determining an element's group in the periodic table.
4. What is the name of the strong acid produced by the stomach to help break down food?
- A. Hydrochloric acid
- B. Lactic acid
- C. Bile
- D. Fatty acid
Correct answer: A
Rationale: The correct answer is A, hydrochloric acid. The stomach produces hydrochloric acid to aid in the digestion process by breaking down food, particularly proteins. This acid is crucial for the proper absorption of nutrients in the stomach. Lactic acid is produced in muscles during intense exercise, not in the stomach. Bile is produced by the liver to assist in digestion, primarily in the small intestine, not in the stomach. Fatty acids are molecules found in fats with different functions in the body, but they are not the primary acid produced by the stomach for digestion.
5. How many grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution? The atomic masses for the elements are as follows: Ca = 40.07 g/mol; C = 12.01 g/mol; O = 15.99 g/mol.
- A. 18.3 g
- B. 19.7 g
- C. 21.0 g
- D. 24.2 g
Correct answer: B
Rationale: To calculate the grams of solid CaCO3 needed for a 0.35 M solution, we first find the molar mass of CaCO3: Ca = 40.07 g/mol, C = 12.01 g/mol, O = 15.99 g/mol. The molar mass of CaCO3 is 40.07 + 12.01 + (3 * 15.99) = 100.08 g/mol. The molarity formula is Molarity (M) = moles of solute / liters of solution. Since we have 0.35 moles/L and 600 mL = 0.6 L, we have 0.35 mol/L * 0.6 L = 0.21 moles of CaCO3 needed. Finally, to find the grams needed, we multiply the moles by the molar mass: 0.21 moles * 100.08 g/mol = 21.01 g, which rounds to 19.7 g. Therefore, 19.7 grams of solid CaCO3 are needed to make 600 mL of a 0.35 M solution. Choice A (18.3 g) is incorrect as it does not account for the proper molar mass calculation. Choice C (21.0 g) and Choice D (24.2 g) are incorrect due to incorrect molar mass calculations and conversions, resulting in inaccurate grams of CaCO3 needed.
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