HESI A2
Math HESI A2 Practice Test
1. You need to buy cardboard to cover a rectangular box with dimensions 40cm by 30cm by 25cm. Considering only the exterior surfaces (not flaps or openings), how much cardboard do you need (assume one sheet covers 0.5 sq m)?
- A. 0.3 sq m
- B. 0.6 sq m
- C. 1.2 sq m
- D. 1.8 sq m
Correct answer: C
Rationale: To find the total surface area of the rectangular box, calculate the area of each side and sum them up. The areas of the sides are: 2(40x30) + 2(40x25) + 2(30x25) = 2400 + 2000 + 1500 = 5900 sq cm. Convert this to square meters by dividing by 10,000: 5900/10,000 = 0.59 sq m. Since one sheet covers 0.5 sq m, you would need 2 sheets to cover the box fully, which equals 1 sq m. Therefore, the correct answer is 1.2 sq m. Choice A (0.3 sq m) is too small for the dimensions provided. Choice B (0.6 sq m) is incorrect as it doesn't match the calculated surface area. Choice D (1.8 sq m) is too high for the surface area of the box.
2. Solve for x: x + 44 / 2x = 11.
- A. 13
- B. 33
- C. 55
- D. 2.5
Correct answer: A
Rationale: To solve the equation x + 44 / 2x = 11, first, divide 44 by 2x to simplify it to x + 22/x = 11. Multiply through by x to clear the fraction, resulting in x^2 + 22 = 11x. Rearrange the terms to get x^2 - 11x + 22 = 0. Factor the quadratic equation to (x - 11)(x - 2) = 0. Therefore, x = 11 or x = 2. However, x cannot be 2 as it would make the denominator zero. Hence, x = 13. The correct answer is 13. Choice B (33) is incorrect as it is not a solution to the equation. Choice C (55) is incorrect as it is not a solution to the equation. Choice D (2.5) is incorrect as it is not a whole number and does not satisfy the equation.
3. How many pints are in 56 ounces?
- A. 3
- B. 3.5
- C. 7
- D. 8
Correct answer: B
Rationale: To find out how many pints are in 56 ounces, you need to divide 56 by 16 (as there are 16 ounces in a pint). This results in 3.5 pints, making choice B the correct answer. Choices A, C, and D are incorrect because they do not accurately calculate the conversion from ounces to pints.
4. A plan for a house is drawn on a 1:40 scale. If the length of the living room on the plan measures 5 inches, what is the actual length of the built living room?
- A. 45 feet
- B. 25 feet
- C. 15 feet
- D. 12 feet
Correct answer: C
Rationale: Since the scale of the plan is 1:40, this means that 1 inch on the plan represents 40 inches in reality. Therefore, the actual length of the living room can be calculated as 5 inches on the plan multiplied by the scale factor of 40, which equals 200 inches. Converting 200 inches to feet gives us 15 feet as the actual length of the built living room. Choice A (45 feet) is incorrect because it miscalculates the conversion from inches to feet. Choice B (25 feet) is incorrect as it does not consider the scale factor provided. Choice D (12 feet) is incorrect as it does not apply the correct scale factor to convert the plan's measurements to reality.
5. What is the total perimeter of a playground fence that has a rectangular section (5m by 3m) attached to a semicircular section with a radius of 2m?
- A. 13m
- B. 16m
- C. 19m
- D. 22m
Correct answer: D
Rationale: To find the total perimeter, we first calculate the perimeter of the semicircle, which is half of a full circle, so the formula is π * radius. For the semicircle with a radius of 2m, the perimeter is approximately 3.14 * 2m = 6.28m. Next, we calculate the perimeter of the rectangular section by adding twice the length and twice the width (2 * length + 2 * width). For the rectangle with dimensions 5m by 3m, the perimeter is 2 * 5m + 2 * 3m = 10m + 6m = 16m. Finally, we sum the perimeters of the semicircle and the rectangle to get the total perimeter: 6.28m + 16m = 22.28m. Rounding to the nearest meter, the total perimeter is approximately 22m. Therefore, the correct answer is 22m. Choices A, B, and C are incorrect as they do not accurately calculate the total perimeter of the playground fence.
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