Nursing Elites

1. When you push a book across a table, the book experiences an equal and opposite force from the table. Why doesn't the table move as well?

• A. The table is much heavier than the book.
• B. The force on the book acts in a different direction.
• C. The table has a much larger surface area, distributing the force over a wider area.
• D. All of the above

Correct answer: A

Rationale: The table is much heavier than the book, so it requires a much larger force to accelerate it. The book is lighter and easier to move, so the force applied to it causes it to move without significantly affecting the table due to the table's greater mass. Newton's third law states that for every action, there is an equal and opposite reaction. In this case, the force exerted on the book by the table is countered by an equal force exerted on the table by the book, but the table's greater mass resists movement. Choice B is incorrect because the forces are equal and opposite, acting in the same direction. Choice C is incorrect as the surface area does not affect the movement of the table in this scenario. Therefore, the correct answer is A, as the table's greater mass prevents it from moving easily when a force is applied.

2. Which of the following produces the first heart sound ('lub')?

• A. The closing of the aortic and pulmonary valves
• B. The closing of the tricuspid and mitral valves
• C. The opening of the aortic and pulmonary valves
• D. The opening of the tricuspid and mitral valves

Correct answer: B

Rationale: The correct answer is B. The first heart sound, known as the 'lub' sound, is produced by the closure of the tricuspid and mitral valves, which are the atrioventricular valves. This sound marks the beginning of systole in the cardiac cycle. Choice A, the closing of the aortic and pulmonary valves, is incorrect as these valves produce the second heart sound ('dub'). Choice C, the opening of the aortic and pulmonary valves, is incorrect because the first heart sound occurs during ventricular contraction (systole). Choice D, the opening of the tricuspid and mitral valves, is incorrect as the 'lub' sound is associated with the closure, not the opening, of these valves.

3. What is the formula to calculate work?

• A. Work = Force × Distance
• B. Work = Mass × Velocity
• C. Work = Power × Time
• D. Work = Energy ÷ Time

Correct answer: A

Rationale: Work is defined as the product of the force applied to an object and the distance over which the force is applied. The formula to calculate work is represented by Work = Force × Distance, where force is the applied force on an object and distance is the displacement over which the force is applied. Therefore, the correct formula to calculate work is Work = Force × Distance. Choice B, 'Work = Mass × Velocity,' is incorrect because work involves force and distance, not mass and velocity. Choice C, 'Work = Power × Time,' is incorrect because work is not directly calculated using power and time. Choice D, 'Work = Energy ÷ Time,' is incorrect because work is not typically calculated by dividing energy by time; rather, it involves the product of force and distance.

4. What is the term for the tiny particles that make up atoms?

• A. Protons
• B. Electrons
• C. Neutrons
• D. Subatomic particles

Correct answer: D

Rationale: The correct answer is 'Subatomic particles.' Subatomic particles are the tiny components that constitute atoms, including protons, neutrons, and electrons. Protons and neutrons are located in the nucleus of an atom, while electrons revolve around the nucleus. Choices A, B, and C specifically refer to individual subatomic particles but do not encompass the complete range of particles within an atom.

5. A 10 kg box rests on a frictionless surface. A horizontal force of 20 N is applied to the box. What is the box's acceleration?

• A. 0.5 m/s²
• B. 1 m/s²
• C. 2 m/s²
• D. 10 m/s²

Correct answer: B

Rationale: The acceleration of an object is given by the formula \(a = \frac{F}{m}\), where \(F\) is the net force acting on the object and \(m\) is the mass of the object. In this case, the net force acting on the box is 20 N, and the mass of the box is 10 kg. Plugging these values into the formula, we get \(a = \frac{20}{10} = 2\) m/s².

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