HESI A2
HESI Exams Quizlet Physics
1. When a charged particle moves through a vacuum at a constant speed, it generates:
- A. An electric field only
- B. A magnetic field only
- C. Both an electric and magnetic field
- D. Neither an electric nor magnetic field
Correct answer: C
Rationale: A moving charged particle generates both an electric field and a magnetic field. The electric field is due to the charge itself, and the magnetic field is produced by the motion of the charge. Choice A is incorrect because a moving charged particle also generates a magnetic field. Choice B is incorrect because a moving charged particle generates both electric and magnetic fields. Choice D is incorrect as a moving charged particle generates fields due to its charge and motion.
2. If a 5-kg ball is moving at 5 m/s, what is its momentum?
- A. 10 kg⋅m/s
- B. 16.2 km/h
- C. 24.75 kg⋅m/s
- D. 25 kg⋅m/s
Correct answer: D
Rationale: The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the mass of the ball is 5 kg and its velocity is 5 m/s. Therefore, the momentum of the ball is 5 kg × 5 m/s = 25 kg⋅m/s. Choice A (10 kg⋅m/s) is incorrect as it does not account for both mass and velocity. Choice B (16.2 km/h) is incorrect as it provides a speed in a different unit without considering mass. Choice C (24.75 kg⋅m/s) is incorrect as it does not correctly calculate the momentum based on the given mass and velocity.
3. Two balloons with charges of 5 μC each are placed 25 cm apart. What is the magnitude of the resulting repulsive force between them?
- A. 0.18 N
- B. 1.8 N
- C. 10−3 N
- D. 5 × 10−3 N
Correct answer: B
Rationale: To find the repulsive force between the two charges, we use Coulomb's law: F = k(q1 * q2) / r^2. Here, k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges (5 μC each), and r is the distance between the charges (25 cm = 0.25 m). Substituting these values into the formula: F = (8.99 x 10^9 Nm^2/C^2)(5 x 10^-6 C)(5 x 10^-6 C) / (0.25 m)^2. Calculating this gives F = 1.8 N. Therefore, the magnitude of the resulting repulsive force between the two balloons is 1.8 N. Choice A, C, and D are incorrect as they do not correctly calculate the force using Coulomb's law.
4. Why are boats more buoyant in salt water than in fresh water?
- A. Salt decreases the mass of the boats.
- B. Salt increases the volume of the water.
- C. Salt affects the density of the boats.
- D. Salt increases the density of the water.
Correct answer: D
Rationale: Salt increases the density of water, making saltwater more buoyant than freshwater. The higher density of saltwater provides more lift to a boat, enabling it to float more easily compared to in freshwater. Choice A is incorrect because salt does not affect the mass of the boats. Choice B is incorrect as salt does not increase the volume of water. Choice C is incorrect since salt affects the density of water, not the boats themselves. Therefore, the correct answer is that salt increases the density of the water, resulting in boats being more buoyant in salt water than in fresh water.
5. A pitcher throws a 45-g baseball at a velocity of 42 meters per second. What is the ball’s momentum?
- A. 0.189 kg⋅m/s
- B. 1.89 kg⋅m/s
- C. 1.07 kg⋅m/s
- D. 0.93 kg⋅m/s
Correct answer: B
Rationale: Momentum is calculated by multiplying mass (in kg) by velocity (in m/s). The mass of the baseball is 0.045 kg (45 grams converted to kg), and the velocity is 42 m/s. Momentum = 0.045 kg × 42 m/s = 1.89 kg⋅m/s. Therefore, the correct answer is 1.89 kg⋅m/s. Choice A is incorrect as it incorrectly converts the mass from grams to kg. Choice C and D are incorrect due to calculation errors.
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