ATI TEAS 7
TEAS 7 practice test free science
1. What is the process of breaking down fatty acids into acetyl-CoA, a key molecule in cellular respiration, called?
- A. Beta-oxidation
- B. Lipolysis
- C. Carbohydrate catabolism
- D. Nucleic acid catabolism
Correct answer: A
Rationale: Beta-oxidation is the correct term for the process of breaking down fatty acids into acetyl-CoA molecules. This essential process takes place in the mitochondria and is a pivotal step in fatty acid metabolism for energy production. Lipolysis, however, refers to the breakdown of fats into fatty acids and glycerol but does not specifically involve the conversion of fatty acids into acetyl-CoA. Carbohydrate catabolism focuses on breaking down carbohydrates into glucose for energy production and is not directly linked to the conversion of fatty acids into acetyl-CoA. Nucleic acid catabolism involves the breakdown of nucleic acids into nucleotides and is not associated with the conversion of fatty acids into acetyl-CoA.
2. Which state of matter has both a definite volume and a definite shape?
- A. Solid
- B. Liquid
- C. Gas
- D. Plasma
Correct answer: A
Rationale: The correct answer is 'Solid.' Solids have both a definite volume and a definite shape because the particles are closely packed together and vibrate in fixed positions. This close arrangement of particles allows solids to maintain their shape and volume, unlike liquids and gases which do not have a definite shape. Liquids take the shape of their container but have a definite volume. Gases, on the other hand, do not have a definite shape or volume as they expand to fill the space available to them. Plasma is a high-energy state of matter where atoms are stripped of their electrons and is not characterized by definite shape or volume.
3. Which of the following is NOT a state of matter?
- A. Solid
- B. Liquid
- C. Gas
- D. Superfluid
Correct answer: D
Rationale: The correct answer is 'Superfluid.' Superfluid is not considered a traditional state of matter. It is a unique phase of matter that displays zero viscosity and flows without losing kinetic energy. Solids, liquids, and gases are the three classical states of matter distinguished by their physical properties and structures. Therefore, choices A, B, and C are considered states of matter, while choice D, superfluid, is not.
4. What type of reaction is represented by the following equation: Fe2O3 (s) + 3H2 (g) -> 2Fe (s) + 3H2O (g)?
- A. Combustion
- B. Decomposition
- C. Single displacement
- D. Redox reaction
Correct answer: C
Rationale: The correct answer is C: Single displacement. This reaction is a single displacement reaction because the iron (Fe) in Fe2O3 is displaced by the hydrogen (H) in H2 to form Fe and H2O. In single displacement reactions, one element replaces another in a compound. Choice A, Combustion, involves a reaction with oxygen typically producing heat, light, and often a flame. Choice B, Decomposition, is when a compound breaks down into simpler substances. Choice D, Redox reaction, involves both reduction and oxidation reactions happening simultaneously, which is not the case in the provided equation.
5. How are sister chromatids distinguished from homologous chromosomes in meiosis I?
- A. Sister chromatids share the same centromere, while homologous chromosomes have different centromeres.
- B. Sister chromatids have identical DNA sequences, while homologous chromosomes have slightly different sequences due to crossing over.
- C. Sister chromatids repel each other, while homologous chromosomes attract each other during synapsis.
- D. Sister chromatids separate during anaphase I, while homologous chromosomes separate during anaphase II.
Correct answer: B
Rationale: In meiosis I, sister chromatids are exact copies of each other, containing identical DNA sequences. On the other hand, homologous chromosomes are pairs of chromosomes, with one inherited from each parent, and they can have different versions of genes due to genetic recombination during crossing over in prophase I. Choice A is incorrect because homologous chromosomes naturally have different centromeres. Choice C is incorrect as sister chromatids and homologous chromosomes do not exhibit repulsion or attraction during synapsis. Choice D is incorrect as sister chromatids separate during anaphase II, not anaphase I, while homologous chromosomes separate during anaphase I.
Similar Questions
Access More Features
ATI TEAS Premium Plus
$149.99/ 90 days
- Actual ATI TEAS 7 Questions
- 3,000 questions with answers
- 90 days access
ATI TEAS Basic
$99/ 30 days
- 3,000 Questions with answers
- 30 days access