subtract 2 58 78 and reduce
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HESI A2

HESI A2 Math Practice Exam

1. Subtract 2 & 5/8 - 7/8 and reduce.

Correct answer: C

Rationale: To subtract 7/8 from 2 & 5/8, you need to borrow 1 whole from the 2, making it 1 whole and 13/8. Then, subtracting 7/8 from 13/8 results in 6/8, which simplifies to 3/4. Therefore, the answer is 1 & 3/4. Choice A (1 & 5/8) is incorrect as the correct answer is 1 & 3/4. Choice B (1 & 6/8) can be simplified to 1 & 3/4, which is the correct answer. Choice D (1 & ¼) is incorrect as the subtraction result is greater than 1, making the whole number part 1.

2. If 7 is to 9 as x is to 63, find the value of x.

Correct answer: A

Rationale: To find the value of x, set up the proportion 7/9 = x/63. Cross multiply to get 7*63 = 9*x. This simplifies to 441 = 9x. Divide both sides by 9 to solve for x, giving x = 49. Therefore, the correct answer is A. Choice B (x = 39), Choice C (x = 50), and Choice D (x = 59) are incorrect as they do not match the correct calculation based on the proportion set up.

3. How many yards are in a mile?

Correct answer: A

Rationale: The correct answer is A: 1,760. According to the standard distance conversion, there are 1,760 yards in a mile. This conversion is widely accepted and used in various fields. Choice B, 1,700, is incorrect as it does not correspond to the standard conversion. Choice C, 1,800, represents a different value and is therefore incorrect. Choice D, 1,750, is not the accurate conversion for yards in a mile and is incorrect.

4. A vitamin's expiration date has passed. It was supposed to contain 500 mg of calcium, but it has lost 325 mg of calcium. How many mg of calcium are left?

Correct answer: A

Rationale: The correct answer is A: 175 mg. The vitamin originally contained 500 mg of calcium. After losing 325 mg, the remaining amount of calcium is calculated as 500 mg - 325 mg = 175 mg. Choice B (135 mg) is incorrect because the vitamin lost more calcium than that. Choices C (185 mg) and D (200 mg) are incorrect as they do not consider the amount of calcium lost from the original 500 mg.

5. A lab needs 200ml of a 5% salt solution. They only have a 10% solution. How much 10% solution and water should be mixed?

Correct answer: B

Rationale: Rationale: 1. Let x be the volume of the 10% solution needed and y be the volume of water needed. 2. The total volume of the final solution is 200ml, so x + y = 200. 3. The concentration of the final solution is 5%, so the amount of salt in the final solution is 0.05 * 200 = 10g. 4. The amount of salt in the 10% solution is 0.1x, and the amount of salt in the water is 0, so the total amount of salt in the final solution is 0.1x. 5. Since the total amount of salt in the final solution is 10g, we have 0.1x = 10. 6. Solving for x, we get x = 100ml. 7. Substituting x =

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