HESI A2
HESI A2 Math Practice Test 2023
1. Solve for x: x/250 = 3/500.
- A. 150
- B. 25.5
- C. 1.5
- D. 60
Correct answer: C
Rationale: To solve for x, cross-multiply: x/250 = 3/500. This simplifies to x = 1.5. Therefore, the correct answer is 1.5. Choice A (150) is incorrect because it does not account for the division by 250. Choice B (25.5) is incorrect as it is not the correct result of the calculation. Choice D (60) is incorrect as it is not the correct result of the calculation either.
2. If a recipe calls for 2 cups of sugar and you want to make half of the recipe, how many cups of sugar do you need?
- A. 1 cup
- B. 1.5 cups
- C. 2 cups
- D. 0.5 cups
Correct answer: A
Rationale: To make half of the recipe that calls for 2 cups of sugar, you would need 1 cup of sugar. Choice A is correct because half of 2 cups is 1 cup. Choice B (1.5 cups) is incorrect as it is three-quarters of the original amount, not half. Choice C (2 cups) is the amount required for the full recipe, not for half. Choice D (0.5 cups) is half of 1 cup, not half of 2 cups.
3. What is the result of adding 9.43 and 11.3?
- A. 20.73
- B. 21.3
- C. 22
- D. 19.5
Correct answer: A
Rationale: The correct answer is A: 20.73. To calculate the sum of 9.43 and 11.3, you simply add the two numbers together. Therefore, 9.43 + 11.3 equals 20.73. Choice B (21.3) is incorrect because it represents the sum of rounding the numbers up. Choice C (22) and choice D (19.5) are also incorrect as they do not accurately reflect the sum of the provided numbers.
4. Solve for x: x + 44 / 2x = 11.
- A. 13
- B. 33
- C. 55
- D. 2.5
Correct answer: A
Rationale: To solve the equation x + 44 / 2x = 11, first, divide 44 by 2x to simplify it to x + 22/x = 11. Multiply through by x to clear the fraction, resulting in x^2 + 22 = 11x. Rearrange the terms to get x^2 - 11x + 22 = 0. Factor the quadratic equation to (x - 11)(x - 2) = 0. Therefore, x = 11 or x = 2. However, x cannot be 2 as it would make the denominator zero. Hence, x = 13. The correct answer is 13. Choice B (33) is incorrect as it is not a solution to the equation. Choice C (55) is incorrect as it is not a solution to the equation. Choice D (2.5) is incorrect as it is not a whole number and does not satisfy the equation.
5. A scientific illustrator uses a scale of 3:1 for drawings of insects. If the length of a cicada in the drawing is 6 centimeters, how long is the actual cicada in real life?
- A. 18 centimeters
- B. 6.3 centimeters
- C. 4.6 centimeters
- D. 4.2 centimeters
Correct answer: A
Rationale: The scale of 3:1 means that for every 3 centimeters in the drawing, it represents 1 centimeter in real life. If the length of the cicada in the drawing is 6 centimeters, in real life, it would be 6 x 3 = 18 centimeters long. Therefore, the actual length of the cicada in real life is 18 centimeters. Choice B, 6.3 centimeters, is incorrect because it does not account for the scale factor. Choices C and D, 4.6 centimeters and 4.2 centimeters respectively, are also incorrect as they do not consider the 3:1 scale used in the drawing.
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