solve for x 5x 10 20
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HESI A2

HESI A2 Math Practice Test 2023

1. Solve for x: 5x + 10 = 20.

Correct answer: A

Rationale: To solve the equation 5x + 10 = 20, first subtract 10 from both sides to isolate the term with x: 5x = 10. Then, divide by 5 on both sides to find the value of x: x = 2. Therefore, the correct answer is A. Choice B is incorrect because x is not equal to 2 but 4. Choice C is incorrect as x is not equal to 5. Choice D is incorrect as x is not equal to 7.

2. What is the result of dividing 3 by 4?

Correct answer: D

Rationale: To divide 3 by 4, we perform the division operation: 3 รท 4 = 0.75. The correct answer is 0.75 (D). Choices A, B, and C are incorrect because they do not result from dividing 3 by 4. Choice A (5.75) is the result of dividing 23 by 4, choice B (5.875) is the result of dividing 7 by 1.2, and choice C (6.25) is the result of multiplying 5 by 1.25.

3. Express 0.75 as a fraction.

Correct answer: B

Rationale: To express 0.75 as a fraction, we write it as 75/100. Simplifying this fraction by dividing both the numerator and denominator by 25 gives us 3/4. Therefore, 0.75 is equivalent to 3/4. Choice A (4/5), Choice C (1/2), and Choice D (1/4) are incorrect fractions and do not represent 0.75.

4. How many pounds are in 80 ounces?

Correct answer: A

Rationale: To convert ounces to pounds, you need to know that there are 16 ounces in a pound. Therefore, to find how many pounds are in 80 ounces, you divide 80 by 16, which equals 5 pounds. Thus, the correct answer is 5 pounds. Choice B, 6 pounds, is incorrect because it doesn't accurately reflect the conversion from ounces to pounds. Choice C, 4 pounds, and Choice D, 3 pounds, are also incorrect as they do not align with the correct conversion factor of 16 ounces to 1 pound.

5. X/4 = 9/x, solve for x.

Correct answer: A

Rationale: To solve X/4 = 9/x, cross multiply to get x^2 = 36. Taking the square root of both sides gives x = 6. Choice A is correct because x = 6 satisfies the equation x^2 = 36. Choices B, C, and D are incorrect as they do not satisfy the equation when substituted back into it.

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