Nursing Elites

1. How are kidney stones formed?

• A. Due to excess water not being reabsorbed
• B. When minerals crystallize in the urine
• C. When electrolytes become too concentrated
• D. All of the above

Correct answer: B

Rationale: Kidney stones are formed when minerals in the urine crystallize and stick together to form solid masses. Excess water not being reabsorbed (option A) does not directly contribute to kidney stone formation. Similarly, electrolytes becoming too concentrated (option C) is not a direct cause of kidney stone formation. The correct answer is B because the crystallization of minerals in the urine leads to the formation of kidney stones.

2. Which of the following is NOT a function of the cardiovascular system?

• A. Transporting oxygen to cells
• B. Maintaining blood pressure
• C. Carrying waste products to the kidneys for removal
• D. Initiating the immune response

Correct answer: D

Rationale: The cardiovascular system is responsible for transporting oxygen to cells (A), maintaining blood pressure (B), and carrying waste products to the kidneys for removal (C). Initiating the immune response (D) is not a function of the cardiovascular system. The immune response is primarily carried out by the immune system, which includes organs like the spleen, thymus, and lymph nodes. Therefore, option D is the correct answer as it pertains to a function outside the scope of the cardiovascular system, making it the odd one out among the given choices.

3. How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?

• A. 31.25 mL
• B. 32 mL
• C. 30 mL
• D. 31.3 mL

Correct answer: B

Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.

4. If a biochemist isolates a large amount of pyruvate, which part of the cell is he working with?

• A. Chloroplasts
• B. Cytoplasm
• C. Mitochondria
• D. Nucleus

Correct answer: B

Rationale: The correct answer is B: Cytoplasm. Pyruvate is a product of glycolysis, a metabolic pathway that takes place in the cytoplasm of the cell. Therefore, a biochemist isolating a large amount of pyruvate would be working with the cytoplasm of the cell. Choice A, Chloroplasts, is incorrect because pyruvate is not produced in chloroplasts, which are responsible for photosynthesis. Choice C, Mitochondria, is incorrect as pyruvate is produced in the cytoplasm before entering the mitochondria for further metabolism. Choice D, Nucleus, is incorrect as the nucleus is not involved in the production or isolation of pyruvate, which is a metabolic intermediate.

5. A person pushes a box across a floor with a constant force. The box eventually comes to a stop due to friction. What happens to the work done by the person?

• A. It increases as the box moves further.
• B. It decreases as the box slows down.
• C. It remains constant throughout the motion.
• D. It becomes zero once the box stops.

Correct answer: D

Rationale: Work done is defined as the product of the force applied and the distance moved in the direction of the force. In this scenario, when the box comes to a stop, the displacement becomes zero, leading to zero work done by the person. Choice A is incorrect as the work done is not increasing, but rather decreasing as the box slows down. Choice B is incorrect because the work done does not decrease as the box slows down; it becomes zero when the box stops. Choice C is incorrect as the work done is not constant but decreases to zero when the box stops.

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