HESI A2
HESI A2 Math Practice Exam
1. Jeff needed a 6 ft. rope. He found 2 pieces of rope and thought maybe he could tie them together. One rope was 40 inches and the other was 36 inches. How long would the rope be, and would he have enough rope if he ties them together?
- A. No, the rope would be 76 inches.
- B. Yes, the rope would be 76 inches.
- C. Yes, the rope would be 6 feet.
- D. No, the rope would be 6 feet.
Correct answer: B
Rationale: To convert 6 feet to inches, we multiply 6 by 12 (1 foot = 12 inches), giving us 72 inches needed. By adding the lengths of the two ropes (40 inches + 36 inches), Jeff would have a total of 76 inches, which is more than the 72 inches required. Therefore, he would have enough rope if he ties them together. Choice A and D are incorrect because they misinterpret the conversion from feet to inches. Choice C is incorrect as it does not consider the actual combined length of the two ropes.
2. How many liters are in 120 milliliters?
- A. 1.2 liters
- B. 12 liters
- C. 1,200 liters
- D. 0.12 liters
Correct answer: D
Rationale: To convert milliliters to liters, divide the milliliters by 1000 since there are 1000 milliliters in a liter. In this case, 120 milliliters divided by 1000 equals 0.12 liters. Therefore, the correct answer is 0.12 liters. Choice A (1.2 liters) is incorrect as it incorrectly moved the decimal point. Choice B (12 liters) is incorrect as it incorrectly multiplied by 10 instead of dividing by 1000. Choice C (1,200 liters) is incorrect as it added an extra zero, resulting in a much larger value.
3. Sergeant Kellogg had his men line up at 3:40 P.M. What would that be in military time?
- A. 340
- B. 3040
- C. 1500
- D. 1540
Correct answer: D
Rationale: In military time, the 24-hour clock is used. 3:40 P.M. in standard time would be 1540 in military time. To convert from standard time to military time, you keep the hour number the same for afternoon and evening hours but add 12 to afternoon hours. Choice A (340) is incorrect as it doesn't follow the military time format. Choice B (3040) is incorrect as military time uses a maximum of four digits. Choice C (1500) is incorrect as it represents 3:00 P.M. in military time, not 3:40 P.M.
4. A roast was cooked at 325°F in the oven for 4 hours. The internal temperature rose from 32°F to 145°F. What was the average rise in temperature per hour?
- A. 20
- B. 32
- C. 28
- D. 37°F/hr
Correct answer: C
Rationale: The temperature increased from 32°F to 145°F, resulting in a total increase of 145°F - 32°F = 113°F. Dividing this total increase by the 4 hours of cooking time gives an average rise of 113°F ÷ 4 = 28.25°F per hour, which can be rounded to 28°F per hour. Therefore, the correct answer is 28. Choice A (20) is incorrect because it does not reflect the actual average rise in temperature per hour. Choice B (32) is incorrect as it does not consider the total temperature increase and divide it by the total hours. Choice D (37°F/hr) is incorrect as it does not match the calculated average rise in temperature per hour.
5. Solve for x: x/250 = 3/500
- A. 1.5
- B. 25.5
- C. 1500
- D. 2.5
Correct answer: A
Rationale: To solve for x in the equation x/250 = 3/500, you can cross-multiply: x*500 = 3*250. Therefore, 500x = 750. Now, divide both sides by 500: x = 750/500. Simplifying, x = 1.5. Therefore, the correct answer is A, 1.5. Choice B, 25.5, is incorrect as it does not match the correct calculation. Choice C, 1500, is incorrect as it is not the result of solving the equation given. Choice D, 2.5, is incorrect as well, as it does not align with the correct value of x obtained from the equation.
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