Nursing Elites

1. Jeff needed a 6 ft. rope. He found 2 pieces of rope and thought maybe he could tie them together. One rope was 40 inches and the other was 36 inches. How long would the rope be, and would he have enough rope if he ties them together?

• A. No, the rope would be 76 inches.
• B. Yes, the rope would be 76 inches.
• C. Yes, the rope would be 6 feet.
• D. No, the rope would be 6 feet.

Correct answer: B

Rationale: To convert 6 feet to inches, we multiply 6 by 12 (1 foot = 12 inches), giving us 72 inches needed. By adding the lengths of the two ropes (40 inches + 36 inches), Jeff would have a total of 76 inches, which is more than the 72 inches required. Therefore, he would have enough rope if he ties them together. Choice A and D are incorrect because they misinterpret the conversion from feet to inches. Choice C is incorrect as it does not consider the actual combined length of the two ropes.

2. A worker in a warehouse ships 9 boxes each day. If every box must contain 3 shipping labels, how many shipping labels does the worker need each day?

• A. 24 labels
• B. 27 labels
• C. 20 labels
• D. 30 labels

Correct answer: B

Rationale: To find the total number of shipping labels needed, multiply the number of boxes by the labels per box: 9 boxes * 3 labels per box = 27 labels. Therefore, the worker needs 27 shipping labels each day. Choice A, 24 labels, is incorrect because it results from multiplying 9 boxes by 3 labels without calculating the correct total. Choice C, 20 labels, is incorrect as it underestimates the total number of labels needed. Choice D, 30 labels, is incorrect as it overestimates the total by multiplying incorrectly.

3. A landscaping plan is drawn on a 1:50 scale. If a deck in the plan measures 12 cm by 10 cm, how large is the deck in real life?

• A. 12 m by 10 m
• B. 6 m by 5 m
• C. 5 m by 2 m
• D. 4 m by 3 m

Correct answer: B

Rationale: Since the landscaping plan is drawn on a 1:50 scale, the real-life dimensions of the deck can be calculated by multiplying the dimensions on the plan by the scale factor. The dimensions given are 12 cm by 10 cm. Multiplying these dimensions by the scale factor of 50 gives us 600 cm by 500 cm, which is equivalent to 6 m by 5 m in real life. Choice A is incorrect as it doesn't consider the scale factor. Choice C and Choice D are incorrect as they are not the result of multiplying the dimensions by the scale factor.

4. A birdbath has a hemispherical bowl with a diameter of 30cm. What is its volume?

• A. 675 cu cm
• B. 1350 cu cm
• C. 2700 cu cm
• D. 4050 cu cm

Correct answer: C

Rationale: To find the volume of a hemispherical bowl, we use half the formula for a sphere's volume: (2/3) * π * (radius)^3. Given the diameter is 30cm, the radius is half of that, which is 15cm. Substitute the radius into the formula: (2/3) * π * (15cm)^3 ≈ 2700 cu cm. Therefore, the correct volume is approximately 2700 cu cm. Choices A, B, and D are incorrect as they do not correctly calculate the volume of the hemispherical bowl.

5. A bookshelf has triangular shelves with a base of 40cm and a height of 30cm. The depth of the shelf is 25cm. What is the volume of each shelf?

• A. 3000 cu cm
• B. 3750 cu cm
• C. 5000 cu cm
• D. 7500 cu cm

Correct answer: B

Rationale: To find the volume of the triangular shelf, first calculate the area of the triangle (1/2 * base * height) which is (1/2 * 40 * 30) = 600 sq cm. Then, multiply this area by the depth of the shelf (600 * 25) = 15000 cu cm. Therefore, the volume of each shelf is 3750 cu cm. Choice A, C, and D are incorrect as they do not correctly calculate the volume based on the dimensions provided.

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