if you compare a 1 m solution of nacl to a 1 m solution of glucose c6h12o6 in water which solution would have the higher boiling point

ATI TEAS 7

TEAS 7 science quizlet

1. If you compare a 1 M solution of NaCl to a 1 M solution of glucose (C6H12O6) in water, which solution would have the higher boiling point?

A. The NaCl solution
B. The glucose solution
C. They would have the same boiling point
D. It depends on the temperature

Correct answer: A

Rationale: 1. Boiling point elevation: When a solute is added to a solvent, it raises the boiling point of the solution compared to the pure solvent. This phenomenon is known as boiling point elevation. 2. Van't Hoff factor: The extent of boiling point elevation depends on the number of particles the solute dissociates into in the solution. NaCl dissociates into two ions (Na+ and Cl-) in water, while glucose does not dissociate into ions. Therefore, NaCl has a higher Van't Hoff factor than glucose. 3. Colligative properties: Boiling point elevation is a colligative property, meaning it depends on the concentration of the solute particles, not the identity of the solute. Since both NaCl and glucose are 1 M solutions, the NaCl solution will have a higher boiling point due to its higher Van't Hoff factor. 4. Conclusion: The NaCl solution

2. Which statement is true regarding aromatic compounds?

A. Contain a ring structure with alternating single and double bonds
B. Readily undergo addition reactions
C. Are easily broken down by water
D. Do not contain any pi (π) bonds

Correct answer: A

Rationale: Aromatic compounds contain a ring structure with alternating single and double bonds, known as a benzene ring. This alternating pattern of bonds gives aromatic compounds their stability and unique properties. Due to this resonance, aromatic compounds are less reactive towards addition reactions. Water does not easily break down aromatic compounds due to their stability from the delocalized electrons in the ring structure. Therefore, the correct statement is that aromatic compounds contain a ring structure with alternating single and double bonds, providing them with stability and unique properties. Choices B, C, and D are incorrect. Aromatic compounds do not readily undergo addition reactions (B), are not easily broken down by water (C), and do contain pi (π) bonds due to the presence of the alternating single and double bonds in the ring structure (D).

3. What is the function of the pons?

A. Center for emotion and motivation
B. Control production of hormones
C. Relay messages from the cortex to the cerebellum
D. Responsible for involuntary actions like breathing

Correct answer: C

Rationale: The correct function of the pons is to relay messages from the cortex to the cerebellum. The pons acts as a bridge between different brain regions, facilitating communication and coordination of movements. Choices A, B, and D are incorrect. The pons is not the center for emotion and motivation, does not control hormone production, and is not primarily responsible for involuntary actions like breathing. Understanding the role of the pons in relaying messages between brain regions is crucial for comprehending its function in the central nervous system.

4. Which of the following blood proteins can destroy pathogens?

A. Complement system
B. Fibrinogen
C. Major histocompatibility complex
D. Platelets

Correct answer: A

Rationale: The correct answer is A: Complement system. The complement system is a vital component of the immune system responsible for destroying pathogens through various mechanisms like promoting inflammation, enhancing phagocytosis, and directly lysing pathogens. Fibrinogen is crucial for blood clotting, the major histocompatibility complex is involved in immune responses, and platelets aid in blood clotting and wound healing. However, none of these directly destroy pathogens as the complement system does.

5. What is the molarity of a solution made by dissolving 4.0 grams of NaCl into enough water to make 120 mL of solution? The atomic mass of Na is 23.0 g/mol, and Cl is 35.5 g/mol.

A. 0.34 M
B. 0.57 M
C. 0.034 M
D. 0.057 M

Correct answer: B

Rationale: To find the molarity, first calculate the moles of NaCl. Moles of NaCl = 4.0 g / (23.0 g/mol + 35.5 g/mol) = 0.068 mol. Next, use the formula for molarity: Molarity = moles of solute / liters of solution. Molarity = 0.068 mol / 0.120 L = 0.57 M. Therefore, the molarity of the solution is 0.57 M. Choice A, 0.34 M, is incorrect as it does not match the calculated molarity. Choice C, 0.034 M, is incorrect as it is a decimal point off from the correct molarity. Choice D, 0.057 M, is incorrect as it does not match the calculated molarity of 0.57 M.