Nursing Elites

1. If y = 4 and x = 3, solve y x³

• A. -108
• B. 108
• C. 27
• D. 4

Correct answer: B

Rationale: With y = 4 and x = 3, the expression is y × x³. Substituting the values, we get 4 × 3³ = 4 × 27 = 108. Therefore, the correct answer is 108. Option A (-108) is incorrect because the negative sign is not part of the result. Option C (27) is incorrect as it only represents x³ without considering the value of y. Option D (4) is incorrect as it represents the initial value of y, not the result of y × x³.

2. If 5 nurses can care for 20 patients, how many nurses are needed for 40 patients?

• A. 7
• B. 8
• C. 9
• D. 10

Correct answer: B

Rationale: If 5 nurses can care for 20 patients, it means each nurse is responsible for 20/5 = 4 patients. To care for 40 patients, we divide the total patients by the number of patients each nurse can care for: 40/4 = 10 nurses. Therefore, 10 nurses are needed for 40 patients. Among the options, the closest number is 8 nurses, making it the correct answer. Choice A, 7 nurses, is insufficient. Choice C, 9 nurses, exceeds the required amount. Choice D, 10 nurses, matches the total number of nurses required, not the closest, making it incorrect.

3. A scientific illustrator uses a scale of 3:1 for drawings of insects. If the length of a cicada in the drawing is 6 centimeters, how long is the actual cicada in real life?

• A. 18 centimeters
• B. 6.3 centimeters
• C. 4.6 centimeters
• D. 4.2 centimeters

Correct answer: A

Rationale: The scale of 3:1 means that for every 3 centimeters in the drawing, it represents 1 centimeter in real life. If the length of the cicada in the drawing is 6 centimeters, in real life, it would be 6 x 3 = 18 centimeters long. Therefore, the actual length of the cicada in real life is 18 centimeters. Choice B, 6.3 centimeters, is incorrect because it does not account for the scale factor. Choices C and D, 4.6 centimeters and 4.2 centimeters respectively, are also incorrect as they do not consider the 3:1 scale used in the drawing.

4. Solve for x: x + 44 / 2x = 11.

• A. 13
• B. 33
• C. 55
• D. 2.5

Correct answer: A

Rationale: To solve the equation x + 44 / 2x = 11, first, divide 44 by 2x to simplify it to x + 22/x = 11. Multiply through by x to clear the fraction, resulting in x^2 + 22 = 11x. Rearrange the terms to get x^2 - 11x + 22 = 0. Factor the quadratic equation to (x - 11)(x - 2) = 0. Therefore, x = 11 or x = 2. However, x cannot be 2 as it would make the denominator zero. Hence, x = 13. The correct answer is 13. Choice B (33) is incorrect as it is not a solution to the equation. Choice C (55) is incorrect as it is not a solution to the equation. Choice D (2.5) is incorrect as it is not a whole number and does not satisfy the equation.

5. A pressure vessel has a cylindrical body (diameter 10cm, height 20cm) with hemispherical ends (same diameter as the cylinder). What is its total surface area?

• A. 785 sq cm
• B. 1130 sq cm
• C. 1570 sq cm
• D. 2055 sq cm

Correct answer: D

Rationale: To find the total surface area, we need to calculate the surface area of the cylindrical body and both hemispherical ends separately. The surface area of the cylinder is the sum of the lateral surface area (2Ï€rh) and the area of the two circular bases (2Ï€r^2). For the hemispheres, the surface area of one hemisphere is (2Ï€r^2), so for two hemispheres, it would be (4Ï€r^2). Given that the diameter of the cylinder and hemispherical ends is 10cm, the radius (r) is 5cm. Calculating the individual surface areas: Cylinder = 2Ï€(5)(20) + 2Ï€(5)^2 = 200Ï€ + 50Ï€ = 250Ï€. Hemispheres = 4Ï€(5)^2 = 100Ï€. Adding these together gives a total surface area of 250Ï€ + 100Ï€ = 350Ï€ cm^2, which is approximately equal to 2055 sq cm. Therefore, the correct answer is D. Choice A (785 sq cm) is incorrect as it is significantly lower than the correct calculation. Choices B (1130 sq cm) and C (1570 sq cm) are also incorrect as they do not reflect the accurate surface area calculation for the given dimensions.

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